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Neporo4naja [7]
3 years ago
8

HELPPP! Line segment DE is a midsegment of АВС. Find the value of x.

Mathematics
1 answer:
Elan Coil [88]3 years ago
8 0

Step-by-step explanation:

The midsegment is half of the side side AC.

Half of 38=18

DE=19

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Perpendicular to y=2x+9 and has the point (4,-1)
Wewaii [24]

Answer: y =  -\frac{1}{2}x + 1

Step-by-step explanation:

      First, we will find the slope. The slope of perpendicular lines are negative reciprocals.

      In this case, the first slope is 2. The negative of 2 is -2, and the reciprocal of -2 is -\frac{1}{2}.

      Now, we will plug in this new slope, the point given, and solve for the <em>b</em>, or the y-intercept.

y = <em>m</em>x + <em>b</em>

(-1) =  (-\frac{1}{2})(4) + <em>b</em>

-1 =  -2 + <em>b</em>

1 = <em>b</em>

     Lastly, we will write our equation.

y = <em>m</em>x + <em>b</em>

y =  -\frac{1}{2}x + 1

          The line is y =  -\frac{1}{2}x + 1, or y = 1 - \frac{x}{2}.

4 0
2 years ago
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Need help on this. Don’t understand a thing and I need to get this done ASAP. If you knew please help. It would be greatly appre
matrenka [14]

Answer:

the Lateral SA is 84

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Step-by-step explanation:

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................... 8x-0.2=9.8
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Answer:

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Step-by-step explanation:

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3 years ago
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(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)
laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

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What is the y-intercept of f(x)=3
HACTEHA [7]

Answer:

B

Step-by-step explanation:

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