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3 years ago

What the expression is?

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

7 0

Answer:

The answer is 29

Stolb23 [73]3 years ago

5 0

Answer:

Step-by-step explanation:

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At what points are the equation y=x^2 and 1/x+2 equal<br><br>

irina [24]

Answer:

Brown, purple, Green and Red/Pink

Step-by-step explanation:

The equations are equal where they intersect on the graph. There are 4 points at which the to graphs intersect. They intersect at the points colored brown, purple, green and red.

6 0

4 years ago

Maximal use of bezels, gradients, and drop shadows make an interface highly user friendly True False

tigry1 [53]

Bezels, gradients, and drop shadows can make an interface user-friendly if used wisely and minimally. If too much, the interface can be distracting. The problem used the term "maximal." This means that the bezels, gradients, and drop shadows are excessively used in an interface. So, the answer to this question is
FALSE
Using too much image effects can make an interface not user-friendly.<span />

5 0

4 years ago

Another equation for 32x - 12.8

Law Incorporation [45]

You can use a calculator and put is where I’d can tell you the answer

8 0

4 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

3 years ago

Tutorial Exercise A boat leaves a dock at 2:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due

ANTONII [103]

Answer:

Both the boats will closet together at 2:21:36 pm.

Step-by-step explanation:

Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).

Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),

Formula : d=v*t

at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

Formula : D= $\sqrt{(x2-x1)^2+(y2-y1)^2}$