All categories

2 years ago

What is the total number of outcomes for choosing a numbered card from 1 to 10 and a number on a

Mathematics

1 answer:

ycow [4]2 years ago

7 0

the total number of out comes would be 16^2 or 256.

some extra things...

A numbered card from 1 - 10 would be 1 over 10 or 10% chance of picking correctly.

a number cube from 1 - 6 would be 1 over 6 or 16.66% chance of picking correctly.

if you want to combine these and pick one from both, it becomes 1 over 16 or 6.25% chance of picking both correctly.

You might be interested in

Help me plz with algebra I will select brainiest!!!

JulsSmile [24]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The top question is the one i need help on (number 1)

dybincka [34]

8x8x8=512
hope this is what its asking

6 0

3 years ago

Read 2 more answers

Find the median of the list 12,18,21,25,30,43

BlackZzzverrR [31]

The median is 21 and 23

4 0

3 years ago

Read 2 more answers

David rents DVDS from a company that changes a $7.00 monthly fee and $1.50 for each dvd rental. He ends up paying $20.50 for the

serious [3.7K]

1.5x + 7 = 20.5
First subtract 7 from both sides
1.5x = 13.5
Then divide both sides by 1.5
x = 9

Let me know in comments if you have questions

3 0

2 years ago

What is the equation of this graphed line?

barxatty [35]

Answer:

$y=-\frac{1}{3}x-5$

Step-by-step explanation:

Given:

The two points on the line are:

$(x_1,y_1)=(-6,-3)\\(x_2,y_2)=(6,-7)$

Now, for a line with two points on it, the slope of the line is given as:

$m=\frac{y_2-y_1}{x_2-x_1}$

For the points $(x_1,y_1)=(-6,-3)\ and\ (x_2,y_2)=(6,-7)$ , slope is:

$m=\frac{-7-(-3)}{6-(-6)}\\m=\frac{-7+3}{6+6}\\m=\frac{-4}{12}=-\frac{1}{3}$

Now, for a line with slope 'm' and a point $(x_1,y_1)$ on it is given as:

$y-y_1=m(x-x_1)$

Plug in all the values and determine the equation of the line. This gives,

$y-(-3)=-\frac{1}{3}(x-(-6))\\\\y+3=-\frac{1}{3}(x+6)\\\\y+3=-\frac{1}{3}x-\frac{1}{3}\times 6\\\\y+3=-\frac{1}{3}x-2\\\\y=-\frac{1}{3}x-2-3\\\\y=-\frac{1}{3}x-5$

Therefore, the equation of the line is:

$y=-\frac{1}{3}x-5$

4 0

3 years ago