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umka21 [38]
3 years ago
11

Kyle works at a donut​ factory, where a​ 10-oz cup of coffee costs 95cents¢​, a​ 14-oz cup costs​ $1.15, and a​ 20-oz cup costs​

$1.50. During one busy​ period, Kyle served 35 cups of​ coffee, using 544 ounces of​ coffee, while collecting a total of ​$43.60 How many cups of each size did Kyle​ fill
Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0
Let s, m, L represent the number of small, medium, and Large cups of coffee Kyle filled.
  s +m +L = 35 . . . . . . . . . . . . . . . served 35 cups
  10s +14m +20L = 544 . . . . . . . . using 544 ounces of coffee
  .95s +1.15m +1.50L = 43.60 . . . while collecting $43.60

Solving these 3 linear equations in 3 unknowns by your favorite method, you find
  Kyle filled 6 small cups (10 oz)
  Kyle filled 16 medium cups (14 oz)
  Kyle filled 13 Large cups (20 oz)

_____
Elimination is a reasonable way to start. Subtract 10 times the first equation from the second, and 0.95 times the first equation from the third. Then you have
  4m +10L = 194
  .2m +.55L = 10.35
Now, you can subtract .05 times the first of these equation from the last to get
  .05L = .65
  L = 13
Back-substituting gets you the values of the other variables.
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The set A={(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,(2,6),(3,6),(4,6),(5,6),(6,6)}

B={(2,2),(4,2),(6,2),(2,4),(2,6),(1,3),(1,5),(1,1),(3,1),(3,3),(3,5),(4,4),(4,6),(5,1),(5,3),(5,5),(6,4),(6,6)}

C={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,3),(2,5),(3,3),(3,5),(3,4),(3,6),(4,1),(4,3),(4,5),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,3),(6,5)}.

A∩B:{(2,2),(4,2),(6,2),(2,4),(2,6),(4,4),(4,6),(6,4),(6,6)}

A∪B={(1,2),(2,2),(4,2),(6,2),(2,4),(2,6),(4,4),(4,6),(6,4),(6,6),(3,2),(5,2),(1,4),(3,4),(5,4),(1,6),(3,6),(5,6),(1,3),(1,5),(1,1)(3,1),(3,3),(3,5),(5,1),(5,3),(5,5)}

A∩C={(1,2),(1,4),(1,6),(3,2),(3,4),(3,6),(5,2),(5,4),(5,6)}

Step-by-step explanation:

6 0
3 years ago
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