1 gallon for $3 is the better deal because you're getting twice as much for the same price
Answer: The toy should be 2.4 inches tall
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Explanation:
First convert 6 ft to inches
6 ft = (6 ft)*(12 in/1 ft) = (6*12) inches = 72 inches
So, 6 ft = 72 inches
The toy is manufactured with a scale of 1:30 meaning that the toy is 1 unit tall compared to the soldier which is 30 units tall. The soldier is 30 times taller than the toy. We can therefore form the ratio
1/30 = x/72
where x is the height of the toy soldier in inches
Cross multiply and solve for x
1/30 = x/72
1*72 = 30*x
72 = 30*x
72/30 = 30*x/30
72/30 = x
x = 72/30
x = 12/5
x = 2.4
So the toy should be 2.4 inches tall.
Note how 30 times 2.4 gives us
30*2.4 = 72
which fits with the theme that the real soldier is 30 times taller than the toy counter part.
Answer:
Each friend ate 4 tacos.
Step-by-step explanation:
"4 of his friends ate s tacos" is unclear. I assume it should be
"4 of his friends ate s tacos each."
total tacos = 2 + 4s = 18
4s = 16
s = 4
His four friends ate a total of 16 tacos, each friend eating 4 tacos.
Ricky's reason, i.e., that 6s = 18, is incorrect.
6s = 4s+2s, where 4s is what his friends ate in total.
That implies that Ricky ate 2s tacos, instead of 2 tacos. If 2s = 2 then s = 1, but then 6s ≠ 18.
C) 3:1
For every 3 people who prefer band A toothpaste 1 person preferred band B toothpaste:
3 to 1=3:1.
Problem 1
Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.
Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.
With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.
Refer to the diagram below.
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Problem 2
I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.
In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.