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kirza4 [7]
3 years ago
7

if thrice my age 6 years ago be subtracted from twice my present age the result is present age then my present age is what​

Mathematics
1 answer:
aleksley [76]3 years ago
8 0

Answer:

9 years

Step-by-step explanation:

Let the present age = x

Age 6 years ago = x - 6

Thrice my age 6 years ago = 3*(x -6) =3x - 3*6 = 3x - 18

Twice my present age = 2 *x = 2x

Thrice my age 6 years ago be subtracted from

twice my present age  = 2x -  (3x - 18)

2x - (3x - 18) = x

2x - 3x  + 18 = x                  

    -x  + 18 = x              {Add x to both sides}

             18 = x + x

              18 = 2x              {Divide both sides by 2}

           18/2 = x

x = 9 years

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