if thrice my age 6 years ago be subtracted from twice my present age the result is present age then my present age is what
1 answer:
Answer:
9 years
Step-by-step explanation:
Let the present age = x
Age 6 years ago = x - 6
Thrice my age 6 years ago = 3*(x -6) =3x - 3*6 = 3x - 18
Twice my present age = 2 *x = 2x
Thrice my age 6 years ago be subtracted from
twice my present age = 2x - (3x - 18)
2x - (3x - 18) = x
2x - 3x + 18 = x
-x + 18 = x {Add x to both sides}
18 = x + x
18 = 2x {Divide both sides by 2}
18/2 = x
x = 9 years
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Answer:
i would think b.. but im not sure
Step-by-step explanation:
translate, call the number, n
Eight more than (8+) twice a number increased by 3 (2(n+3)) is equal to (=) 79 (79)
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Add up all the sides only, not the area inside
The answer is C. Write 3x as a difference, and Use the commutative property to reorder the terms.
