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Travka [436]
3 years ago
14

Use the ranges to explain why the secant function can attain the value of 2 but the cosine function cannot.

Mathematics
1 answer:
Sonbull [250]3 years ago
6 0

Answer:

i need points rq thanks so much

Step-by-step explanation:

imma go waste these points now

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Classify each pair of labeled angles as complementary, supplementary, or neither.
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Supplementary, complementary, neither
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What is |-8|<br> 0-16<br> O 8<br> O 8<br> O 16
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8

Explanation

The absolute value of a negative number turns into a positive
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Complex numbers simplify square roots of negative numbers
Bogdan [553]

Lets do

\\ \sf\longmapsto \sqrt{-100}

\\ \sf\longmapsto \sqrt{-(10)^2}

\\ \sf\longmapsto \sqrt{10^2}\sqrt{-1}

\\ \sf\longmapsto 10i

Write in standard form

\\ \sf\longmapsto 10i

\\ \sf\longmapsto \boxed{0}+\boxed{10}i

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3 years ago
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I WILL GIVE BRAINLY! The surface of a table to be built will be in the shape shown below. The distance from the center of the sh
ki77a [65]

Answer:

  • draw lines center to vertex
  • 43.5 square inches
  • 261 square inches

Step-by-step explanation:

<u>Part A</u>:

The area can be decomposed into triangles by drawing a line from the center to each vertex of the hexagon.

__

<u>Part B</u>:

The area of each triangle is given by the triangle area formula:

  A = (1/2)bh

  A = (1/2)(10 in)(8.7 in) = 43.5 in²

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<u>Part C</u>:

The area of the table top is 6 times the area of one triangle:

  surface area = 6(43.5 in²) = 261 in²

3 0
3 years ago
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A network provider investigates the load of its network. The number of concurrent users is recorded at fifty locations (thousand
beks73 [17]

Answer:

see explaination

Step-by-step explanation:

Using the formulla that

sum of terms number of terms sample mean -

Gives the sample mean as \mu=17.954

Now varaince is given by

s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97

and the standard deviation is s=\sqrt{9.97}=3.16

b) The standard error is given by

\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45

c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1

Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88

d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05

Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96

or a number which is less than 15.83-1.5(4.05)=9.76

As there is no such number so the given sample has no outliers

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