Answer:
33
Step-by-step explanation:
take the total and then subtract by 34 to get 33
Let z = 3x+2. Then, by substitution, your equation is
.. z^2 +7z -8 = 0
_____
This equation can be factored as
.. (z +8)(z -1) = 0
.. x = -8 or +1
Then
.. 3x +2 = -8 or +1
.. 3x = -10 or -1
.. x = -10/3 or -1/3
Answer:
A=8.4063
Step-by-step explanation:
Be the functions:

according the graph:
=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B3%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%20%3D3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-3%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%3D3%28%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%7D%20%7D%20%5C%2C%20dx%20-%5Cint%5Climits%5E1_7%20%7B%5Cfrac%7B1%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%29%3D3%5Blnx-%5Cfrac%7B1%7D%7Bx%7D%5D%281-7%29%3D3%5B%28ln7-ln1%29-%28%5Cfrac%7B1%7D%7B7%7D-1%29%5D%3D3%5B%281.945-0%29-%280.1428-1%29%5D%3D3%2A%281.945%2B0.8571%29%3D3%2A2.8021%3D8.4063u%5E%7B2%7D)
Answer: (13.4996, 32.5004)
Step-by-step explanation:
The confidence interval for mean difference is given by :-
,
where
= sample mean difference .
= critical t value (two-tailed)
SE= Standard error.
Given :

SE= 4.2
Now, the confidence interval for mean difference will be :-
Hence, the required confidence interval : (13.4996, 32.5004)
Answer:
Let's see what to do buddy...
Step-by-step explanation:
_________________________________



Subtract the sides of the equation plus<em> </em><em>1</em><em>1</em> :


Subtract the sides of the equation plus <em>1</em><em>0</em><em>x</em>


Divided the sides of the equation by <em>9</em><em> </em>


And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️