Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
The answer is most likely B. :)
Answer:

Step-by-step explanation:
Given
Paper = 20 slips
Word: PENNSYLVANIA
Required
Determine P(Multiple of 4 and V)
The sample size of the 20 slips is:

The outcomes of multiples of 4 is:


So, the probability of multiples of 4 is:


The sample size of PENNSYLVANIA is:

The outcome of V is:

So, the probability of V is:

So, the required probability is: P(Multiple of 4 and V)




Express as percentage


Answer: 1091
Step-by-step explanation: add the numbers
Answer:
0.6%??
I did 3 divided by 500 and got 0.006 then moved the decimal places to transform the decimal to fraction which ends up being 0.6%