<span>Y is directly proportional to x^2. It could be represented by the expression:
y </span>α x^2
We can make it into an equality by inserting the proportionality constant, k.
y = kx^2
k would be constant for any value of y with a corresponding value of x. We solve the problem by this concept as follows:
y1/(x1)^2 = y2/(x2)^2
10/(x1)^2 = y2/(x1/2)^2
10/4 = y2
Therefore, when the value of x is halved, y is equal to 10/4.
2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer:
d the other equations the total is 35. this one the total would be 55
Answer:
Option D.
x can take values from 15downwards. It can't be 16 because the expression clearly states that x is less than 16. So x can take value from any number below 16.
