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uysha [10]
3 years ago
10

For each graph, determine whether x and y are proportional.

Mathematics
1 answer:
Aloiza [94]3 years ago
8 0
The answer to this question is graph 3 :)) it is
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3a+2b=193<br><br> Find a and b
galina1969 [7]
Hope this made sense

6 0
3 years ago
HELP PLEASE I WILL GIVE YOU BRAINLIEST
Alja [10]
The answer is 600 because of the miles
3 0
3 years ago
This is my last question can someone help me with my homework.
shutvik [7]

9514 1404 393

Answer:

  C, A, A

Step-by-step explanation:

In general, you ...

  • identify the coefficients of one of the variables
  • swap them, and negate one of them
  • multiply the corresponding equations by the "adjusted" coefficients.

__

In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:

  multiply equation 2 by -4 . . . (eliminates x)

Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:

  multiply equation 1 by 3 . . . (eliminates y)

These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.

__

The other problems are worked in a similar fashion.

8 0
3 years ago
41. Suppose a family drives at an average rate of 60 mi/h on the way to visit relatives and then at an average rate of 40 mi/h o
Afina-wow [57]

Answer:

The answer is below

Step-by-step explanation:

a) Let x represent the time taken to drive to see the relatives and let d be the distance travelled to go, hence:

60 mi/h = d/x

d = 60x

When returning, they still travelled a distance d, since the return trip takes 1 h longer than the trip there, therefore:

40 mi/h = d/(x+1)

d = 40(x + 1) = 40x + 40

Equating both equations:

60x = 40x + 40

60x - 40x = 40

20x = 40

x = 40/20

x = 2 h

The time taken to drive there = x = 2 hours

b) The time taken for return trip = x + 1 = 2 + 1 = 3 hours

c) The distance d = 60x = 60(2) = 120 miles

The total distance to and fro = 2d = 2(120) = 240 miles

The total time to and fro = 2 h + 3 h = 5 h

Average speed = total distance / total time = 240 miles / 5 h = 48 mi/h

5 0
3 years ago
What is the answer for (-3)+4x +2+2x +2x
sineoko [7]

Answer:

<h2>(-3) + 4x + 2 + 2x + 2x = 8x - 1</h2>

Step-by-step explanation:

(-3) + 4x + 2 + 2x + 2x     <em>combine like terms</em>

= (4x + 2x + 2x) + (-3 + 2)

= 8x - 1

8 0
3 years ago
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