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3 years ago

What is the minimum value of the objective function, C with given constraints?

Mathematics

2 answers:

tankabanditka [31]3 years ago

8 0

Yea I think it’s A 10

san4es73 [151]3 years ago

6 0

Answer:

A 10

Step-by-step explanation:

You might be interested in

Which equation represents the hyperbola in general form?

valina [46]

ANSWER

$9 {y}^{2} - 4 {x}^{2}- 36y + 16x - 16 = 0$

EXPLANATION

The standard equation of the hyperbola is

$\frac{ {(y - 2)}^{2} }{4} - \frac{ {(x - 2)}^{2} }{9} = 1$

We multiply through by 36 to obtain:

$9 {(y - 2)}^{2} - 4( {x - 2)}^{2} = 36$

We now expand to get,

$9( {y}^{2} - 4y + 4) - 4( {x}^{2} - 4x + 4) = 36$

Expand :

$9 {y}^{2} - 36y + 36 - 4 {x}^{2} + 16x - 16 = 36$

To get the general form, we equate everything to zero to get,

$9 {y}^{2} - 4 {x}^{2}- 36y + 16x - 16 = 0$

The correct choice is D.

7 0

3 years ago

Find the measure of side XY.

Ymorist [56]

Answer:

XY = 18

Step-by-step explanation:

The figures are similar so the ratios of corresponding sides are equal, that is

$\frac{XY}{BC}$ = $\frac{YZ}{CD}$ , substitute values

$\frac{XY}{12}$ = $\frac{15}{10}$ ( cross- multiply )

10 XY = 180 ( divide both sides by 10 )

XY = 18

4 0

3 years ago

Passes through (1,12) and has a vertex (10,-4)

agasfer [191]

Answer: 16/81 (x-10)^2 -4

Step-by-step explanation:

To write a vertex equation with just a point and the vertex, you have to figure out the variables.

In vertex form, the equation is y = a (x-h)^2 + k

Your y is 12, x = 1, h = 10, and k = -4

Plug everything into equation

12 = a (1 - 10)^2 -4

12 = a (-9)^2 - 4

12 = 81a - 4

16 = 81a

16/81 = a

Now you know what the 'a' value is.

If you graph 16/81 (x-10)^2 -4 , you will get a point at (1,12) and a vertex of (10,-4)!

I hope this helps!

3 0

4 years ago

Giving brainliest to the answer who gives step by step examples clearly!

Anarel [89]

Hi there!

This should be easy,lol!

Answer:

$\sqrt[3]{-128} = \boxed{-128 \sqrt{3} }$ (Decimal: -221.702503)

$\sqrt[3]{162} = \boxed{162 \sqrt{3} }$ (Decimal: 280.592231)

$\sqrt[3]{-1000x^4} = \boxed{-1732.050808x^4}$

Sorry bout the explanation thingy. Their really long -.-!

But the last one is short so i'll put it for you!

Step-by-step explanation:

∴!For the last one!∴

$\sqrt[3]{-1000x^4}$

Simplifies to:

$= - 1732.050808 * x^4$

$= - 1732.050808 * ( x * x * x * x)$

$= - 1732.050808x^4$

Have a great day/night!

7 0

3 years ago

Read 2 more answers

Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the

MAVERICK [17]

The functions are illustrations of composite functions.

The soil temperature at 2:00pm is 67

The given parameters are:

$\mathbf{I(h) =\frac{12h - h^2}{36}}$ ---- the function for sun intensity

$\mathbf{T(I) =\sqrt{5000I}}$ -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

$\mathbf{h = 2:00pm - 6:00am}$

$\mathbf{h = 8}$

Substitute 8 for h in $\mathbf{I(h) =\frac{12h - h^2}{36}}$ , to calculate the sun intensity

$\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}$

$\mathbf{I(8) =\frac{32}{36}}$

$\mathbf{I(8) =\frac{8}{9}}$

Substitute 8/9 for I in $\mathbf{T(I) =\sqrt{5000I}}$ , to calculate the temperature of the soil

$\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}$

$\mathbf{T(8/9) =\sqrt{4444.44}}$

$\mathbf{T(8/9) =66.67}$

Approximate

$\mathbf{T(8/9) =67}$

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

5 0

2 years ago