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VLD [36.1K]
3 years ago
15

Look at the triangle: A right angle triangle is shown with hypotenuse equal to 10 centimeters. An acute angle of the triangle is

labeled as x degrees. The side adjacent to the acute angle has length 6 centimeters and the side opposite to the acute angle has length 8 centimeters. What is the value of tan x°?
Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0
Tan x°= Opposite/ adjacent<span>so tan </span>x°=86
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Find an equation in slope intercept form of a line having slope 6 and y-intercept 2
xz_007 [3.2K]

Answer:

<h2>y = 6x + 2</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have the slope <em>m = 6</em>, and the y-intercept <em>b = 2</em>.

Substitute:

y=6x+2

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algol [13]

Answer:

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

Step-by-step explanation:

The mass flow rate dQ(t)/dt = mass flowing in - mass flowing out

Since 5 g/L of salt is pumped in at a rate of 4 L/min, the mass flow in is thus 5 g/L × 4 L/min = 20 g/min.

Let Q(t) be the mass present at any time, t. The concentration at any time ,t is thus Q(t)/volume = Q(t)/10. Since water drains at a rate of 4 L/min, the mass flow out is thus, Q(t)/10 g/L × 4 L/min = 2Q(t)/5 g/min.

So, dQ(t)/dt = mass flowing in - mass flowing out

dQ(t)/dt = 20 g/min - 2Q(t)/5 g/min

Since the salt just begins to be pumped in, the initial mass of salt in the tank is zero. So Q(0) = 0

So, the initial value problem is thus

dQ(t)/dt = 20 - 2Q(t)/5 , Q(0) = 0

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erik [133]
Add them all together and there is your sum
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scoundrel [369]

Answer:

7 daisies

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76 ÷ 4 =19

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7 daisies

3 0
3 years ago
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