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VLD [36.1K]
3 years ago
15

Look at the triangle: A right angle triangle is shown with hypotenuse equal to 10 centimeters. An acute angle of the triangle is

labeled as x degrees. The side adjacent to the acute angle has length 6 centimeters and the side opposite to the acute angle has length 8 centimeters. What is the value of tan x°?
Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0
Tan x°= Opposite/ adjacent<span>so tan </span>x°=86
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Select all the factors of: 7x2 − 28 options: 7 7x (x + 2) (x − 2) (x2 + 4)
Salsk061 [2.6K]

Answer:

7(x-2)(x+2)

Step-by-step explanation:

7x^2 -28

Factor out a 7

7(x^2 -4)

The terms inside the parentheses is the difference of squares, so it is factorable  (a^2-b^2) = (a-b)(a+b)

7(x-2)(x+2)

8 0
3 years ago
Find the slope of the line that passes through (-3,-1) and (-5,4)
tester [92]

Line is Passing through the Points (-3 , -1) and (-5 , 4)

Slope of a Line Passing through two points (x₁ , y₁) and (x₂ , y₂) is given by :

\heartsuit\;Slope(m) = \frac{y_1 - y_2}{x_1 - x_2}

here x₁ = -3 and x₂ = -5 and y₁ = -1 and y₂ = 4

\heartsuit\;Slope(m) = \frac{-1 - 4}{-3 + 5} = \frac{-5}{2}

3 0
3 years ago
Evaluate using integration by parts ​
PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

I(n)=\displaystyle\int x^ne^x\,\mathrm dx

One round of IBP, setting

u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx

\mathrm dv=e^x\,\mathrm dx\implies v=e^x

gives

\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx

I(n)=x^ne^x-nI(n-1)

This is called a power-reduction formula. We could try solving for I(n) explicitly, but no need. n=5 is small enough to just expand I(5) as much as we need to.

I(5)=x^5e^x-5I(4)

I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)

I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)

I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)

I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))

Finally,

I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C

so we end up with

I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C

I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C

and the antiderivative is

\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C

8 0
3 years ago
Cynthia, a resident of Ottawa, earns $41,875 annually. If the Canadian government levies an income tax of 18. 6% on Cynthia’s ta
a_sh-v [17]

The total amount of annual take-home pay of Cynthia is $34,086.25

<h3>What is income tax?</h3>

Income tax is a tax applied on individuals or entities concerning income or profit earned by them.

Cynthia earns $41,875 annually.

If the Canadian government levies an income tax of 18.6% on Cynthia’s tax bracket.

It can be calculated as

41,875 × 18.6%

41,875 × 18.6/100 = 7,788.75

The annual take-home pay

41,875 - 7,788.75 = $34,086.25

Thus, The total amount of annual take-home pay is $34,086.25.

Learn more about income tax;

brainly.com/question/27153555

5 0
2 years ago
Read 2 more answers
What is the sum of 9/10+8/100
ArbitrLikvidat [17]
9/10 + 8/100

9/10 + 2×4/25×4

Common denominator is 50.

9/10 + 2/25.

5×9/5×10 + 2×2/2×25

45/50 + 4/50

= 49/50
6 0
3 years ago
Read 2 more answers
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