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Alex777 [14]
3 years ago
13

Bryce grew 3 1/2 inches each year for the past 4 years. How many inches total has Bryce grown in the past 4 years?​

Mathematics
1 answer:
juin [17]3 years ago
7 0

Answer:

14

Step-by-step explanation:

3 1/2 multiply by 4 equals 14

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Shaun's savings can be modeled by the regression equation y = 6x^2 + 75x+200. Which of the following is the best prediction for
kipiarov [429]

Answer:

Option D

Step-by-step explanation:

The equation to predict the amount saved is

y = 6x ^ 2 + 75x + 200.

Assuming that the variable x represents the saving months, then substitute x = 25 in the quadratic equation and solve for y.

y = 6 (25) ^ 2 +75 (25) +200\\\\y = \$\ 5,825

The answer is the option D  $5,825

3 0
3 years ago
You are a nascar fan that collects cars that are 1:64 scale to the original car. If your collection has cars that are 3 inches i
erik [133]
Length = 3 in * 64 =192
: 1 foot = 12 inches
192 : 12 = 16 ft
Answer:
The true length of a vehicle is 16
good luck and may i be marked as brainliest please
3 0
3 years ago
Read 2 more answers
How many models of 100 do you need to make 3,200
Sever21 [200]

I believe the answer is 32 models of 100

6 0
3 years ago
Read 2 more answers
Anybody know this answer?​
V125BC [204]

Answer:

y = -4/5x + 3

Step-by-step explanation:

Chose any two points on the line:

(5, -2)

(-5, 6)

Slope = (y2 - y1) / (x2 - x1)

6 -(-2) / -5 - 5

8 / -10

-4/5

Equation:

y = mx + b

Plug in x and y using any coords and then plug in m (the slope):

-2 = -4/5 * 5 + b

-2 = -20/4 + b

-2 = -5 + b

Add 5 on both sides:

3 = b

Now our equation is:

y = -4/5x + 3

Please let me know if I've done something wrong!

5 0
3 years ago
The polygons are regular polygons. Find the area of the shaded region to the nearest tenth.
Paha777 [63]

Answer:

128.8 cm²

Step-by-step explanation:

In the image attached below, the regular polygon is a square which is composed of a small square and a large square. In a square, all the sides are equal.

For the small square, half of the diagonal is 4 cm, therefore the length of the diagonal is 8 cm (2 × 4 cm). Let the length of the side be a cm, using Pythagoras theorem:

a² + a² = 8²

2a² = 64

a² = 32

a = √32 = 5.7 cm

The area of the small square = length × length = 5.7 × 5.7 = 32.5 cm²

For the large square, half of the diagonal is 9 cm, therefore the length of the diagonal is 18 cm (2 × 9 cm). Let the length of the side be b cm, using Pythagoras theorem:

b² + b² = 18²

2b² = 324

b² = 162

b = √162 = 12.7 cm

The area of the large square = length × length = 12.7 × 12.7 = 161.3 cm²

The area of the shaded region = Area of large square - Area of small square = 161.3 cm² - 32.5 cm² = 128.8 cm²

4 0
3 years ago
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