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3 years ago

Worth 10 points It’s a picture so it’s clear

Mathematics

2 answers:

JulijaS [17]3 years ago

7 0

It’s A because a rectangle has 2 pairs of equal sides if it was a square A could be an answer but it’s a rectangle so it’s answer A

gregori [183]3 years ago

5 0

A. All sides are congruent.
Explanation:
Choice a is NOT a property of the sides of a rectangle because a rectangle does NOT have equal length of sides. Thats a squarw

Choice b is a property of the sides of a rectangle because the consecutive sides (sides that have the same endpoint/connected) are perpendicular. Thats why rectangles have 2 pairs of 90° angles.

Choice C is true because the opposite sides of a rectangle must have same length of sides to form a pair of parallel sides, which is important for a rectangle

Choice D is also true because 2 pairs of parallel sides is important for a rectangle.

Im sorry if i didnt explain this well for you.
Pls say if im correct, if i am brainliest please!
-have a nice day
SpaceMarsh

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2 years ago

What is the value of a1 of the geometric series? Sigma-Summation Underscript n = 1 Overscript infinity EndScripts 12 (negative o

worty [1.4K]

Answer:

Step-by-step explanation:

The given geometric series is

$\sum_{n = 1}^{ \infty} 12( { - \frac{1}{9} })^{n - 1}$

We want to determine the first term of this geometric series.

Recall that the explicit formula is

$a_{n} = 12( { - \frac{1}{9} })^{n - 1}$

To find the first term, we put n=1 to get:

$a_{1} = 12( { - \frac{1}{9} })^{1 - 1}$

This gives us:

$a_{1} = 12( { - \frac{1}{9} })^{0}$

$a_{1} = 12(1) = 12$

Therefore the first term is 12

6 0

3 years ago

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Nana76 [90]

70 I’m pretty sure I’m correct sorry if I’m not:( I’m not to good with math

3 0

3 years ago

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What can this simplify to?

Mkey [24]

→ Chapter : Exponentiation ←
≡ We know that:
⇔ $\frac{a^{x}}{a^{y}}=a^{(x-y)}$
⇔ $\frac{1}{a^{-b}}=a^{b}$

≡ Solution:
⇒ $\frac{4^{2}g^{3}p^{-2}}{4^{5}g^{12}m^{-5}}$
⇒ $[4^{(2-5)}].[g^{(3-12)}].[p^{-2}].[m^{5}]$
⇒ $[4^{-3}].[g^{-9}].[p^{-2}].[m^{5}]$
∴ $\boxed{\frac{1}{64}g^{-9}p^{-2}m^{5}}$ or $\boxed{\frac{m^{5}}{64g^{9}p^{2}}}$

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3 years ago

5. Which equation is of a circle that has a center at

Basile [38]

Answer:

$\large\boxed{D.\ (x-3)^2+(y+2)^2=81}$