Question

Simplify the following expression (-5x + 6x2) - (6x2 – 5x)

Answer 1

Answer:

0

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Distributive Property

Algebra I

• Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

(-5x + 6x²) - (6x² - 5x)

Step 2: Simplify

1. [Distributive Property] Distribute negative:                                                    -5x + 6x² - 6x² + 5x
2. [Subtraction] Combine like terms (x²):                                                             -5x + 5x
3. [Addition] Combine like terms (x):                                                                   0

Answer 2

Answer:

❊ $\large{ \tt{STEP - BY - STEP \: EXPLANATION}} :$

♡ Firstly , Here are some of the questions & their answers which should be known before simplifying the given expression :

Q. Do I have to change the sign of each term of second expression while subtracting ?

Ans : Yep! While subtracting , sign of each term of the second expression changes whereas In addition , sign of each term in the expressions remains unchanged.

Q. What do you mean by Like terms & Unlike terms ?

Ans : Well , Like terms are those which have the same base whereas Unlike terms are those which have the different base [ For eg : In 4x , 2y , 3x & 4y , 4x & 3x are like terms and 2y and 4y are like terms ]. Also Remember : Only coefficients of like terms can be added or subtracted.

The Question / Answer part ends up here. Now , Let's get started for simplifying the given expression :

$\large{ \bf{❊ \: ( - 5 {x}^{} + 6 {x}^{2} ) - (6 {x }^{2} - 5x)}}$

$\large{ \bf{ ↬ \: - 5x + 6 {x}^{2} - 6 {x}^{2} + 5x}}$

$\large{ \bf{↬ - 5x + 5x + 6 {x}^{2} - 6 {x}^{2} }}$

-Here , We can see the like terms with different signs. So, they cancel out each other.

$\large{ \bf{↬ \: \cancel{5x} + \cancel{5x}} + \cancel{6 {x}^{2}} - \cancel{6 {x}}^{2} }$

-We're left with nothing , So the answer would be ' 0 ' .

$\boxed{ \large{ \bf{↬0}}}$

$\boxed{ \boxed {\large{ \tt{⟿ \: OUR\: FINAL \: ANSWER : \boxed{ \underline{ \bf{0}}}}}}}$

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