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nadya68 [22]
3 years ago
9

Can anyone tell me correctly​

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0

\large\underline\red{\sf \implies Solution :- }

1) A figure formed by line segments only is called a <u>polygon</u><u> </u> .

2) Perimeter of a regular polygon is <u>Number </u><u>of </u><u>sides </u><u>×</u><u> </u><u>Measure </u><u>of </u><u>each </u><u>side </u><u>.</u>

3) Perimeter of a irregular polygon is <u>sum </u><u>of </u><u>all </u><u>sides </u><u>.</u>

4) Two circles with same centre but different radii is called <u>Concentric </u><u>circles</u><u>.</u>

5) Ratio of circumference of circle to its diameter is <u>pie </u> and is named by Greek letter <u>π </u>.

6) Distance around the circle is called<u> </u><u>circumference</u><u>.</u>

7) A chord of the circle contains exactly <u>two points</u> on a circle.

8) 1 hectare = <u>1</u><u>0</u><u>,</u><u>0</u><u>0</u><u>0</u><u> </u><u>m²</u>

<h3><u>I </u><u>hope</u><u> </u><u>it </u><u>helped </u><u>ツ</u></h3>
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the answer is 5/8 :)

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3 years ago
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Find the value of r so the line that passes through each pair of points has the given slope.
3241004551 [841]

Answer:

r = 1

Step-by-step explanation:

slope = change in y / change in x, so:

change in y / change in x  = 2/3

5 - r / 7 - 1 = 2/3

5 - r / 6 = 2/3

\frac{5-r}{6}=\frac{2}{3}

now solve this equation.

first, multiply both sides by 6 to get rid of the fraction:

5 - r = 4

subtract 5 from both sides

-r=-1

multiply both sides by -1

r=1

7 0
3 years ago
Difference of two whole numbers is 33 and its ratio is 2:5 then find those<br> numbers.
S_A_V [24]

Answer:

Step-by-step explanation:

Let the two whole numbers be 5x and 2x then

by the question

5x - 2x = 33

3x = 33

x = 33/3

x = 11

Therefore the numbers are

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hope it helps:)

8 0
2 years ago
Please help
Aloiza [94]
A=10x(15x)-p(4x)^2

A=150x^2-16px^2

A=(150-16p)x^2
6 0
3 years ago
3<br>Find the value of a <br>in the equation,(3+4√3)(2-a√3)=-18+2√3​
ankoles [38]

Given:

The equation is:

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

To find:

The value of a.

Solution:

We have,

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

On simplification, we get

(3)(2)+(4\sqrt{3})(2)+(3)(-a\sqrt{3})+(4\sqrt{3})(-a\sqrt{3})=-18+2\sqrt{3}

6+8\sqrt{3}-3a\sqrt{3}-4a(3)=-18+2\sqrt{3}

6+8\sqrt{3}-3a\sqrt{3}-12a=-18+2\sqrt{3}

(6-12a)+(8-3a)\sqrt{3}=-18+2\sqrt{3}

On comparing both sides, we get

6-12a=-18

-12a=-18-6

a=\dfrac{-24}{-12}

a=2

And,

8-3a=2

-3a=2-8

a=\dfrac{-6}{-3}

a=2

Therefore, the value of a is 2.

3 0
2 years ago
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