All categories

3 years ago

Can anyone tell me correctly

Mathematics

1 answer:

BaLLatris [955]3 years ago

4 0

$\large\underline\red{\sf \implies Solution :- }$

1) A figure formed by line segments only is called a polygon  .

2) Perimeter of a regular polygon is Number of sides × Measure of each side .

3) Perimeter of a irregular polygon is sum of all sides .

4) Two circles with same centre but different radii is called Concentric circles.

5) Ratio of circumference of circle to its diameter is pie  and is named by Greek letter π .

6) Distance around the circle is called circumference.

7) A chord of the circle contains exactly two points on a circle.

8) 1 hectare = 10,000 m²

<h3>I hope it helped ツ</h3>

You might be interested in

In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.

bezimeni [28]

Given:

In the circle, $m(\overarc{VUX})=152^\circ$ and $m(\angle MUV)=77^\circ$ .

To find:

The following measures:

(a) $m\angle VUX$

(b) $m\angle UXW$

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

$m(VUX)=2\times m\angle VWX$

$152^\circ=2\times m\angle VWX$

$\dfrac{152^\circ}{2}=m\angle VWX$

$76^\circ=m\angle VWX$

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

$m\angle VUX+m\angle VWX=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle VUX+76^\circ=180^\circ$

$m\angle VUX=180^\circ-76^\circ$

$m\angle VUX=104^\circ$

Now,

$m\angle UXW+m\angle UVW=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle UXW+77^\circ =180^\circ$

$m\angle UXW=180^\circ-77^\circ$

$m\angle UXW=103^\circ$

Therefore, $m\angle VUX=104^\circ$ and $m\angle UXW=103^\circ$ .

7 0

2 years ago

The angle of elevation to the sun is 24°. What is the length of the shadow cast by a person 1.82 m tall? A. 0.81 m B. 1.99 m C.

Zanzabum

Answer:

C. 4.09 m

Step-by-step explanation:

Let the length of the shadow cast by a person be x m.

$\tan \: 24 \degree = \frac{height \: of \: person}{length \: of \: the \: shadow} \\ \\ 0.4452286853 = \frac{1.82}{x} \\ \\ x = \frac{1.82}{0.4452286853} \\ \\ x = 4.08778693 \: m \\ x = 4.09 \: m$

7 0

3 years ago

20 POINTS HELP PLEASE: A diver descends to a location of -50 1/4 meters relative to the surface of the water. He then descends a

vlada-n [284]

Answer:

[14 1/2]

Step-by-step explanation:

4 0

3 years ago

PLEASE ALSO EXPLAIN HOW TO SOLVE THIS. 20 POINTS

eimsori [14]

B.) Hibiscus Street

The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept

So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.

Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.

A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.

B.) Hibiscus Street
* Yes. A Hibiscus is a flower, so this name is suitable.

C.) Oak Street
* Nope. Not only is this a tree instead of a flower, but there's already an Oak street. So bad choice.

D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.

6 0

3 years ago

G(1) = 0 = lgn= ) +m g(n) = g(n - 1) +n = - n g(2) =

yKpoI14uk [10]

Answer:

g(1) = 0

lgn= ) +m

g(n) = g(n - 1) +n

g(2) =12

Step-by-step explanation:

12345678910

6 0

2 years ago

Can anyone tell me correctly​

Can anyone tell me correctly