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3 years ago

How do i solve the equation 6+x=21

Mathematics

2 answers:

Trava [24]3 years ago

6 0

Subtract 6 to both sides.
X is left on its own.
X= 15

Musya8 [376]3 years ago

4 0

answer: 15

Step-by-step explanation: you would take the 21 and subtract 6 from it and you get 15

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If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?

Papessa [141]

5/11 = 18/y
5 y = 18 · 11
5 y = 198
y = 198 : 5
y = 39.6

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2 years ago

What is an algebraic expression for 58 less than a number n?

Korvikt [17]

Answer:

n-58

Step-by-step explanation:

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2 years ago

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Consider the following simplified algebraic expression. 10 x squared y + 6 x squared minus 7 y squared minus 6 Which could be th

Dmitrij [34]

2 y squared minus 3 x minus 4 8 x squared

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2 years ago

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If 47400 dollars is invested at an interest rate of 7 percent per year, find the value of the investment at the end of 5 years f

Anni [7]

Answer:

Part A) Annual $\$66,480.95$

Part B) Semiannual $\$66,862.38$

Part C) Monthly $\$67,195.44$

Part D) Daily $\$67,261.54$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part A) Annual

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=1$

substitute in the formula above

$A=\$47,400(1+\frac{0.07}{1})^{1*5}$

$A=\$47,400(1.07)^{5}$

$A=\$66,480.95$

Part B) Semiannual

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=2$

substitute in the formula above

$A=\$47,400(1+\frac{0.07}{2})^{2*5}$

$A=\$47,400(1.035)^{10}$

$A=\$66,862.38$

Part C) Monthly

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=12$

substitute in the formula above

$A=\$47,400(1+\frac{0.07}{12})^{12*5}$

$A=\$47,400(1.0058)^{60}$

$A=\$67,195.44$

Part D) Daily

in this problem we have

$t=5\ years\\ P=\$47,400\\ r=0.07\\n=365$

substitute in the formula above

$A=\$47,400(1+\frac{0.07}{365})^{365*5}$

$A=\$47,400(1.0002)^{1,825}$

$A=\$67,261.54$

8 0

2 years ago

A standard showerhead in Nathan's house dispenses 11 gallons of water per minute. Nathan changed this showerhead to an energy-sa

Fynjy0 [20]

The new shower head dispenses 3 gallons of water per minute, as shown in the equation y = 3x.

So, 3 x 8 = 24.

Then, to find out how much he saves each day, you would find how much he used before,

11 x 8 = 88

Next we want to see how much Nathan saved, so we subtract the total,

88 - 24 = 64

Nathan saved 64 gallons.

7 0

2 years ago

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