Answer:
well it cant start off in the middle of the graph most graphs you start from the very beginning like lets just say we start at 11 and go all the way to the end so kinda like a straight line
Step-by-step explanation:
Answer:
y = -7, y = -3
Step-by-step explanation:
(y - 3)² = 2y² + 4y + 30
expand:
y² - 6y + 9 = 2y² + 4y + 30
subtract 30 from both sides
y² - 6y + 9 - 30= 2y² + 4y + 30 - 30
simplify:
y² - 6y - 21 = 2y² + 4y
subtract 4y from both sides
y² - 6y - 21 -4y = 2y² + 4y - 4y
simplify:
y² - 10y - 21 = 2y²
subtract 2y² from both sides
y² - 10y - 21 - 2y² = 2y² - 2y²
simplify:
-y² - 10y - 21 = 0
solve y by quadratic equation
- (-10) ± √ (-10² - 4(-1)(21)
y = --------------------------------------
2(-1)
y = -7, y = -3
the way to answer this is you have find out coordinates of BC and since i cant see the graph im no help. y will equal whatever you can get from there .
Answer:
f(x) = -3(x+3)(x-1)
Step-by-step explanation:
x = -3 & 1; f(x) = 9
f(x) = a(x-r1)(x-r2)
f(0) = a(x-r1)(x-r2) = 9; 9 = a(0-(-3))(0-1)
9 = a(3)(-1); 9 = a(-3)
a = -3
f(x) = -3(x+3)(x-1)
