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tatyana61 [14]
3 years ago
8

What is the answer to 6x+15=3x+8

Mathematics
1 answer:
miskamm [114]3 years ago
6 0

Answer:

x = -7/3

Step-by-step explanation:

6x+15=3x+8

Subtract 3x from each side

6x-3x+15=3x-3x+8

3x+15 = 8

Subtract 15 from each side

3x+15-15 = 8-15

3x=-7

Divide each side by 3

3x/3 = -7/3

x = -7/3

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Here's an experiment you can try. Start by folding an ordinary sheet of typing paper exactly in half. Then fold it in half over
Katyanochek1 [597]
First fold = .02
2nd fold =   .04
3rd fold =   .08
4th fold =    .16
5th fold =     .32
6th fold = .64 cm
7 0
4 years ago
Read 2 more answers
The original rectangle has a perimeter of 16
zaharov [31]

As we can see that the sides of the rectangle have been doubled

6.2 ft changed to 12.4 ft

Now when the sides have been doubled

the Perimeter will also be doubled

So the perimeter of new rectangle should be the double the perimeter of old rectangle

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Option C is correct

7 0
3 years ago
The Kendal Company manufactures automobile engine parts. Running the manufacturing operations requires 12 watts (units of electr
Monica [59]

24 because when you plug in 0 for both x and y:  

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4 0
3 years ago
A dozen eggs cost 3.84 at this rate how much would 50 eggs cost
Zina [86]

Answer:

50 eggs would cost 16$

Step-by-step explanation:

A dozen eggs is 12. So for 4 dozen eggs, you get 48. 48 eggs is 15.36$. If you divide the 3.84 to 12, you will get the individual price for each egg. The individual price for each egg is .32 cents. You need to add 2 more eggs to the 4 dozen to get 50 eggs. You times .32 to 2 and you get .64. After that you add .64 to the price of the 4 dozen eggs and you will get 16$

Simple version:

dozen eggs =12, cost 3.84$

4 dozen eggs= 48, cost 15.36$

3.84$ divided by 12 = .32 cents (price of the individual egg)

Add two of the individual eggs together and add it to 15.36$

:)

5 0
3 years ago
Dada a Matriz A= [1 -2 1 ][-3 1 4] [0 6 8] , escreva uma matriz B diferente de A, tal que detA =detB.
Mariulka [41]

Use o fato de que o determinante de qualquer matriz quadrada é o mesmo da sua transposta.

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\mathbf B=\mathbf A^\top=\begin{bmatrix}1&-3&0\\-2&1&6\\1&4&8\end{bmatrix}

3 0
4 years ago
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