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KatRina [158]
3 years ago
8

What is the least common multiple between 8 10 and 12

Mathematics
1 answer:
DochEvi [55]3 years ago
3 0
The LCM is the lowest number that is a multiple of all three numbers. 
First, list the multiples of each number
8: 8, 16, 24, 32,40 48, 56, 64, 72, 80, 88, 96, 104, 112, 120
10: 10, 20, 30 40, 50, 60, 70, 80, 90, 100, 110, 120
12: 12, 24, 36, 48, 60, 72, 84, 96, 108, 120

The LCM is 120 because there is no lower number that is a multiple of all three numbers.
Hope this helped!
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The diameter of a circle is 9 centimeters. Find the area to the nearest tenth.
Umnica [9.8K]

Answer:

63.6 square cm

Step-by-step explanation:

d  = 9 \: cm \implies \: r = 4.5 \: cm \\ area \: of \: circle \\  = \pi {r}^{2}  \\  = 3.14 \times ( {4.5})^{2}  \\  = 3.14 \times 20.25 \\  = 63.585 \\  = 63.6 \:  {cm}^{2}  \\

8 0
3 years ago
Identify a transformation of the function f(x) = (x) by observing the equation of the function g(x) = (x)+56.
umka2103 [35]

Answer:

A: a vertical shift 56 units upward I believe

7 0
3 years ago
Hoping someone can help me. <br> Will give Brainliest for the RIGHT answer!
V125BC [204]

Answer:

  It does not converge.

Step-by-step explanation:

The ratio between terms is 3/2, which is greater than 1, so the sum cannot converge. Each term added to the sum is larger than the one before it.

8 0
3 years ago
How far is the point described by the ordered pair (4,5)<br>from the x axis?​
weeeeeb [17]

Answer:

<h2>The point is 4 units away from the x-axis.</h2>

Step-by-step explanation:

The given ordered pair is (4, 5).

Remember, in a ordered pair, the first number is about the number of units used horizontally, and the second number is about the number of units used vertically.

So, this point is 4 units right side of the origin and 5 units upside of the origin.

Therefore, the point is 4 units away from the x-axis.

5 0
3 years ago
Show whether each value in the set {2,3,4} is a solution of the equation x + 2 = 6.
enyata [817]

Answer:

4

Step-by-step explanation:

Plug in each given value into the expression to see if it is true.

Set given: {2 , 3  , 4}

Equation given: x + 2 = 6

First, plug in 2 for x. When x = 2:

x + 2 = 6

(2) + 2 = 6

4 ≠ 6.

Next, plug in 3 for x. When x = 3:

x + 2 = 6

(3) + 2 =6

5 ≠ 6.

Finally, plug in 4 for x. When x = 4:

x + 2 = 6

(4) + 2 = 6

6 = 6 (True).

In the given set, only 4 complete the equation.

~

7 0
3 years ago
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