You mean situation, when a^b < a.
There are two ways:
But exponent function a^b has to be increasing so a>1
So first solution: a>1 and 0<b<1. Examples:
and second way:
Exponent function a^b has to be decreasing, so 0<a<1
Second solution: a<1 and b>1. Examples:
(5b+xyz_6) xyx+ That is the right answe Im super positive it may seem wrong bit I got. you...
Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Answer:
Step-by-step explanation:
the minimum of f is for x = 1 and f(1)=0
f is decreasing for x<=1 and increasing for x>=1
so the domain is 
x>=1 so x is positive and we can take the square root
so 
