Find the missing the side of the triangle. 19New A. 73‾√ in B. 72‾√ in C. 75‾√ in D. 77‾√ in
1 answer:
By applying Pythagorean's theorem, the missing side of this right-angled triangle is: A. 7√3 inches.
<h3>How to find the missing side?</h3>By critically observing the triangle shown in the image attached below, we can logically deduce that it is a right-angled triangle. Thus, we would find the missing side by applying Pythagorean's theorem:
z² = x² + y²
Also, the sides of this right-angled triangle are:
- Hypotenuse = 14 inches.
- Opposite side = x inches.
- Adjacent side = 7 inches.
Substituting the given parameters into the formula, we have;
14² = x² + 7²
196 = x² + 49
x² = 196 - 49
x² = 147
x = √147
x = √49 × √3
x = 7√3 inches.
Read more on Pythagorean theorem here: brainly.com/question/23200848
#SPJ1
You might be interested in
The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.
A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.
A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.
A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.
These are due to the Doppler effect, the equation of frequency detected by the observer as
where
, v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.
Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.
To learn more about frequency click here brainly.com/question/26177128
#SPJ4