Check the picture below.
thus is at 0 = -16t² + 96t +640,
![\bf 0=-16t^2+96t+640\implies 0=-16(t^2-6t-40) \\\\\\ 0=t^2-6t-40\implies 0=(t-10)(t+4)\implies t= \begin{cases} \boxed{10}\\ -4 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%200%3D-16t%5E2%2B96t%2B640%5Cimplies%200%3D-16%28t%5E2-6t-40%29%0A%5C%5C%5C%5C%5C%5C%0A0%3Dt%5E2-6t-40%5Cimplies%200%3D%28t-10%29%28t%2B4%29%5Cimplies%20t%3D%0A%5Cbegin%7Bcases%7D%0A%5Cboxed%7B10%7D%5C%5C%0A-4%0A%5Cend%7Bcases%7D)
well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.
Answer:
3. C=4a
Step-by-step explanation:
600/150 = 4 (one square foot = $4)
The correct answer is 41/25
Step-by-step explanation:
First we need to set up an equation so
12.50=4x+2.50
Simplify each side by subtracting the initial fee of 2.50
10=4x
divide by 4 to isolate x
2.5=x
You can park for 2.5 hours with your budget
Answer:
x² + 4x + 20 = 12x - 5
x² + 4x - 12x + 20 + 5 = 0
x² - 8x + 25 = 0
Δ = √b² - 4ac
= √(-8)² - 4×1×25
= √64-100
= √(-36)
x ∉ R