Answer:
Ivy is 6 years old and Rose is 12 years old.
Step-by-step explanation:
To solve this problem, two variables are necessary since we have two unknown variables: Ivy's age and Rose's age.
Ivy's age will be 
and Rose's age will be 
"Ivy is half as old as her sister":
this will be our <u>fist equation.</u>
"In six years, Ivy will be two-thirds as old as Rose"
in six years Ivy will have 
years, and Rose will have 
years, so for this sentence we have the equation:
this will be our <u>second equation.</u>
Substituting the value of x from the first equation into the second, and solving for y(Rose):
Rose is 12 years old.
and Ivy (using the fist equation):
Ivy is 6 years old.
The answer should be A. For example, if x = 1, and the ratio between x and y is y is 5 times greater than x, then y would equal 5, which is only true in A.
Or, use the number 5 as an example. If x = 5, and the ratio between x and y is y is 5 times greater than x, then y is 5.
And if you put that into A, y = 5x, it becomes 25 = 5(5)
Then 25 = 25, which is true!
Answer:
Step-by-step explanation:
First, we are going to find the painted area of his house. We know that the total area he needs to paint is 4000 square meters, so 4000 is the area of this house. Now, to find the 62.5% of that area, we are going to multiply it by
:
Painted area=
Now, to find <span>rate, in square feet per hour, we are going to divide the painted area by the number of hours:
Rate=</span>
We can conclude that Kyler paints at a rate of
434.78 square feet per hour.
Answer:
Option b
Step-by-step explanation:
Given that For a particular course, the pass rate for the 16-week format is 59%. A team of faculty examine student data from 40 randomly selected accelerated classes and determine that the pass rate is 78%.
we have to find whether taking a class in a short-term format (8 weeks instead of 16 weeks) increase a student’s likelihood of passing the course
Since pass rate for 16 weeks is 59% we check whether for 8 weeks is more than this.
So correct null and alternative hypotheses for this research question
would be:
b.H0: p = 0.59; Ha: p > 0.59
Option b is right.
