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andre [41]
3 years ago
10

Miguel had 24 quarters and 42 nickels in his bank. His dad

Mathematics
1 answer:
velikii [3]3 years ago
6 0
183 is the total amount of how much coins he has 58 quarters and then he has 125 nickels
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The volume of a cube is 729 cubic feet . What is the side length of the cube ?
Vadim26 [7]

Side length of cube = 9 feet

3 0
3 years ago
Read 2 more answers
Explain your answer please ;w; : Change -2Y - 2X = -6 to the slope intercept form of the equation of a line.
Serhud [2]

Answer:

y = -x + 2

Step-by-step explanation:

The desired equation must have the form y = mx + b.

Start with -2Y - 2X = -6 and solve for y:              y + x = 2

Now solve this result for y:  

y = -x + 2

8 0
3 years ago
Consider the following pair of equations:
frozen [14]
X+4=y=-2x-2
x+4=-2x-2
add 2x to both side
3x+4=-2
minus 4 both sides
3x=-6
divide 3
x=-2

sub back
y=x+4
y=-2+4
y=2

(x,y)
(-2,2)
3 0
3 years ago
Find the remainder when f(x)= 8x^3+ 4x^2<br> 13x + 3 is divided by 2x + 5.
Scrat [10]

Answer:

-129

Step-by-step explanation:

2x+5=0

x=-5/2 [By the remainder theorem]

f(-5/2)=8(-5/2)^3+4(-5/2)^2+13(-5/2)+3

=-125+25-65/2+3

=-129.

5 0
3 years ago
(HURRY! I'M BEING TIMED)Write the partial fraction decomposition of the rational expression.
Aleonysh [2.5K]

Answer:

The partial fraction decomposition is \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}.

Step-by-step explanation:

Partial-fraction decomposition is the process of starting with the simplified answer and taking it back apart, of "decomposing" the final expression into its initial polynomial fractions.

To find the partial fraction decomposition of \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}:

First, the form of the partial fraction decomposition is

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{A}{x + 1}+\frac{B}{\left(x + 1\right)^{2}}+\frac{C}{x + 2}

Write the right-hand side as a single fraction:

                             \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B}{\left(x + 1\right)^{2} \left(x + 2\right)}

The denominators are equal, so we require the equality of the numerators:

             - 4 x^{2} + 13 x - 12=\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B

Expand the right-hand side:

           - 4 x^{2} + 13 x - 12=x^{2} A + x^{2} C + 3 x A + x B + 2 x C + 2 A + 2 B + C

The coefficients near the like terms should be equal, so the following system is obtained:

\begin{cases} A + C = -4\\3 A + B + 2 C = 13\\2 A + 2 B + C = -12 \end{cases}

Solving this system, we get that A=50, B=-29, C=-54.

Therefore,

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}

7 0
3 years ago
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