Answer:
x = -5, y = -6, z = -3
Step-by-step explanation:
Given the system of three equations:
Write the augmented matrix for the system of equations
Find the reduced row-echelon form of the augmented matrix for the system of equations:
Thus, the system of three equations is
From the last equation:
Substitute it into the second equation:
Substitute y = -6 and z = -3 into the first equation:
Answer:
c
Step-by-step explanation:
Hope this helps.
I'll do problem 1 to get you started.
The vertical sides are 3 and x for the left and right figures.
The horizontal sides are 15 and 60 for the left and right figures.
The corresponding sides form fractions which are equal (due to the nature of the similar polygons)
3/x = 15/60
3*60 = x*15 ... cross multiply
180 = 15x
15x = 180
x = 180/15 .... divide both sides by 15
x = 12
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Another way you can see this is note how the jump from 15 to 60 is "times 4", so the jump from 3 to x must also be "times 4" to keep the same proportion
3 ---> x = 3*4 = 12
Or you could set up the proportion
60/15 = x/3
4 = x/3
x/3 = 4
x = 3*4
x = 12
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<h3>Final Answer: 12</h3>
I'm not sure because u don't have a pic of the trapezoid.
Answer:
4x^2 -25
Step-by-step explanation:
The other factor of the difference of squares is the "conjugate" of the given one: (2x -5). Then their product is ...
(2x +5)(2x -5) = (2x)^2 -(5)^2 = 4x^2 -25
