Answer:
<em>Rate of Pratap in still water is 4.5 miles/hour and rate of current is 0.5 miles/hour.</em>
Step-by-step explanation:
Pratap Puri rowed 10 miles down a river in 2 hours, but the return trip took him 2.5 hours.
We know that, 
So, the <u>speed of Pratap with the current</u> will be:
miles/hour
and the <u>speed of Pratap against the current</u> will be:
miles/hour.
Suppose, the rate of Pratap in still water is
and the rate of current is
.
So, the equations will be........

Adding equation (1) and (2) , we will get......

Now, plugging this
into equation (1), we will get.....

Thus, Pratap can row at 4.5 miles per hour in still water and the rate of the current is 0.5 miles/hour.
Answer:
see below
Step-by-step explanation:
The first equation is in slope-intercept form, so you can see that the boundary line has a slope of -2 and goes through the point (x, y) = (0, -4). Since the comparison is "<", the line is dashed and shading is below it.
The second equation is that of a vertical boundary line at x=-3. It is solid, because the comparison includes the "equal" case. Shading is to the right of it, where x values are greater than -3.
Answer:
$51.2
Step-by-step explanation:
If you subtract 64 to 20% then you end up with $51.2