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VARVARA [1.3K]
3 years ago
11

Your Neighbor has a square-shaped pool with side lengths of 3a^5. What is the area of the pool?

Mathematics
2 answers:
lbvjy [14]3 years ago
7 0
  • Square Area: A=s^2 , with s = length of side

Plug in the side length into the square area and solve for the area as such:

A=(3a^5)^2\\A=9a^{10}

<u>The area of the pool is 9a^10 un^2.</u>

mrs_skeptik [129]3 years ago
4 0

if a square-shaped pool side lengths are 3a^5 the area is A= (3a^5)x(3a^5) = 9a^ 5+5= 9a^ 10. Hope this helps!

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g100num [7]
The answer here is C.

Explanation:
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8 0
2 years ago
Convert the angle \theta=\dfrac{8\pi}{9}θ=
Olegator [25]

Answer:

160°

Step-by-step explanation:

-Given the angle in radians as \theta=\dfrac{8\pi}{9}\ rad

-We know that  1 \ rad=\frac{180}{\pi}\textdegree

-Let our angle theta be X

#We therefore equate and cross multiply:

1\ rad=\frac{180}{\pi}\\\\\frac{8\pi}{9}=x\\\\\therefore X=\frac{180}{\pi}\times \frac{8\pi}{9}\\\\=160\textdegree

Hence, angle θ is 160°

8 0
2 years ago
Which is equivalent to 3.25%?
Ratling [72]

Answer:

The first choice.

Step-by-step explanation:

hope this helps!

6 0
2 years ago
Read 2 more answers
13. In ADGE,DG = 8,GE = 17, and DE = 15. What is the length of DF? Round to the nearest hundredth.
Ronch [10]

Answer:

Step-by-step explanation:

The trick is not to get all caught up in Pythagoras. There is a much simpler way to do it. Find the area of the triangle two different ways. DG and DE are at right angles. That is one way to find area. The other is use the height (DF) and multiply that by the hypotenuse GE.

DG*DE/2 = GE * DF/2            Multiply both sides by 2

DG*DE = GE * DF

DG = 8

DE = 15

GE = 17

8*15 = 17* DF

120 = 17 * DF                         Divide by 17

120/17 = DF

DF = 7.06

7 0
3 years ago
Here are some point to help with your difficulties Hope you have a good day :)
Arlecino [84]

Answer:thanks

Step-by-step explanation:

8 0
3 years ago
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