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irinina [24]
3 years ago
9

Thomas and his sister Lauren are competing in a running race. When Thomas is 0.7 miles from the finish line, he notices that his

sister Lauren has fallen. If Thomas runs one-eighth of a mile back to help his sister, how far BACK is he from the finish line?
Mathematics
1 answer:
ratelena [41]3 years ago
4 0

Answer:

ummmmm 0.825

Step-by-step explanation:

im pretty sure thats correct i havent done math like that in a while let me know if its right :)

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A researcher has developed a new drug designed to reduce blood pressure. In an experiment, 21 subjects were assigned randomly to
Paladinen [302]

Answer:

Step-by-step explanation:

Hello!

The objective of the research is to compare the newly designed drug to reduce blood pressure with the standard drug to test if the new one is more effective.

Two randomly selected groups of subjects where determined, one took the standard drug (1- Control) and the second one took the new drug (2-New)

1. Control

X₁: Reduction of the blood pressure of a subject that took the standard drug.

n₁= 23

X[bar]= 18.52

S= 7.15

2. New

X₂: Reduction of the blood pressure of a subject that took the newly designed drug.

n₂= 21

X[bar]₂= 23.48

S₂= 8.01

The parameter of study is the difference between the two population means (no order is specified, I'll use New-Standard) μ₂ - μ₁

Assuming both variables have a normal distribution, there are two options to estimate the difference between the two means using a 95% CI.

1) The population variances are unknown and equal:

[(X[bar]₂-X[bar]₁)±t_{n_1+n_2-2;1-\alpha /2}*(Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2}  })]

t_{n_1+n_2-2;1-\alpha /2}= t_{23+21-2;1-0.025}= t_{42;0.975}= 2.018

Sa=\sqrt{\frac{(n_1-1)*S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{22*7.15^2+20*8.01^2}{42} }= 7.57

[23.48-18.52]±2.018*(7.57*\sqrt{\frac{1}{21} +\frac{1}{23}  })]

[0.349; 9.571]

2) The population variables are unknown and different:

Welche's approximation:

[(X[bar]₂-X[bar]₁)±t_{Dfw;1-\alpha /2}*( \sqrt{\frac{S_1^2}{n_1} +\frac{S_2^2}{n_2} })]

Df_{w}= \frac{(\frac{S_1^2}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S_1^2}{n_1} )^2}{n_1-1}+ \frac{(\frac{S_2^2}{n_2} )^2}{n_2-1}  } =  \frac{(\frac{7.15^2}{23} +\frac{8.01^2_2}{21} )^2}{\frac{(\frac{7.15^2}{21} )^2}{20}+ \frac{(\frac{8.01^2}{23} )^2}{22}  } = 42.85= 42

t_{Df_w;1-\alpha /2}= t_{42; 0.975}=  2.018

[(23.48-18.52)±2.018\sqrt{\frac{7.15^2}{23} +\frac{8.01^2}{21} }]

[0.324; 9.596]

I hope this helps!

4 0
3 years ago
This graph shows the solution to which inequality (3 3) (-3 -1)
Digiron [165]

Answer:

B

Step-by-step explanation:

since the graph shows dotted line the sign has to be < or > so C and D eliminated from your answer

y>2/3 x +1 is your answer (B)

5 0
4 years ago
Read 2 more answers
PLEASE ANSWER RIGHT AEAY
madam [21]

Answer:

y=Sin(x-\frac{\pi}{4})

Step-by-step explanation:

The basic graph of y = Sin(x), starts at x = 0.

Looking at the graph, the basic sin curve starts at x = π/4

So this function is the parent sin function shifted π/4 units to the right.

<u>Note:</u>

y = Sin(x-a)  is the parent function ( y= Sinx) shifted a units right

y = Sin(x+a)  is the parent function shifted a units left

<em>Since this function is shifted </em>π/4 units right, the equation would be:

y = Sin (x-π/4)

The third answer choice is right.

5 0
3 years ago
A105<br> B360<br> C117<br> D 103<br><br> Help me please
serg [7]

Answer:

its D 103°

Step-by-step explanation:

Sum of a pentagon=540

117+100+115+105+x=540

437+x=540

x=540-437

x=103°

3 0
3 years ago
The shape of the top surface of a table is a trapezium. Find its area if its parallel
AleksandrR [38]

Step-by-step explanation:

enjoyyyyyyyyyyyy broooooooo

4 0
3 years ago
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