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kiruha [24]
3 years ago
11

What is the equation of the line that passes through the point(−7,−1) and has a slope of 1?

Mathematics
1 answer:
bonufazy [111]3 years ago
4 0

Answer:

y=x+6

Step-by-step explanation:

Put (-7,-1) into

y-y1=m(x-x1) form, and m=1 (the slope)

y+1=1(x+7)

y+1=x+7

y=x+6

Happy Holidays!

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2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de
Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

               M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let (x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

⇒ d=\sqrt{(2-5)^2+(4-3)^2}

⇒d=\sqrt{9+1}

⇒d=\sqrt{10}   ....(1)

Now, we find the length of M'K'

let (x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)

d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}

⇒ d^{'}=\sqrt{(-2+5)^2+(3-4)^2}

⇒d^{'}=\sqrt{9+1}

⇒d^{'}=\sqrt{10} .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct


3 0
4 years ago
Read 2 more answers
► 00:00
SSSSS [86.1K]

Answer:

16 oz, 12 oz, 4 oz

Step-by-step explanation:

Since 1 pound is equal to 16 ounces, and you can only use each weight once or not at all, you can determine how much is needed by simply adding.

2 pounds is equal to 32 ounces.

To achieve 32 ounces, you can use a 16 ounce weight, which will then bring the scale to need 16 ounces.

After this you can youse a 12 ounce weight, which brings it down to 4 ounces.

The last weight needed is the 4 ounce weight which will then level out the balance scale.

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Help!!! I need the answer ASAP!!!
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Step-by-step explanation:

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Six nickel is what Percent of a dollar
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