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3 years ago

What is the answer to x-9<15

Mathematics

2 answers:

Furkat [3]3 years ago

6 0

Answer:

the answer is anything less than 24

Step-by-step explanation:

docker41 [41]3 years ago

3 0

$x - 9 < 15 = x - 9 + 9 < 15 + 9$

$\times < 24$

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For every 20 apples there is one(1) tree.

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3 years ago

Math tangent of a circle Also sorry my sister got a hold of it ASAP!!!

sweet-ann [11.9K]

Imagine we drew a line from the centre (2,0) to the point (0,4).

Essentially the line we drew from the centre to that point on the circle is perpendicular to the tangent line slope-wise.

The slope of that line from the centre to the point is -2 based on the slope's equation or formula.

slope = $\frac{y2-y1}{x2-x1}=\frac{4-0}{0-2} =-2$

Therefore the tangent equation's slope is 1/2 since any perpendicular line's slope is the negative reciprocal of the original line's slope.

By using the point-slope form, we must have the point on the tangent plane (0,4) and the slope we found which is 1/2.

$y - 4 = \frac{1}{2}(x-0)\\ y= \frac{1}{2}x + 4$

Hope that helps!

7 0

2 years ago

Consider the surface given by

Mazyrski [523]

This is just simple. For example you have a plane of the form x=a, then you just substitute x with a, and you'll get an equation with y and z only, hence you have a 2-d trace of the intersection. It is just similar for y=b and z=c.

(1) At z=1.5, 2x^2 + 5y^2 + 1.5^2 = 4
2x^2 + 5y^2 = 1.75
Now you have an ellipse in the z=1.5 plane as your trace.

(2) At x=1, 2(1)^2 + 5y^2 + z^2 = 4
5y^2 + z^2 = 2
Now you have an ellipse in the x=1 plane as your trace.

(3) At z=0, 2x^2 + 5y^2 + (0)^2 = 4
2x^2 + 5y^2 = 4
Now you have an ellipse in the z=0 plane as your trace.

(4) At y=0, 2x^2 + 5(0)^2 + z^2 = 4
2x^2 + z^2 = 4
Now you have an ellipse in the y=0 plane as your trace.

5 0

4 years ago

I added a picture : Determine which of the lines, if any, are parallel or perpendicular. Explain.

exis [7]

Answer:

1. line a and c and parallel. line b is perpendicular with line a and c. 2. line b and c and parallel. line a is perpendicular to lines b and c. 3. y= -3x + 3 4. y=(5/3)x - 9

Step-by-step explanation:

To find parallel and perpendicular, make the slope opposite and find b by plugging in the points. Parallel is the same slope.

5 0

3 years ago

I need help ASAP! It's urgent.. PLISSSSS

natali 33 [55]

Answer:

a) 6 mins

b) 70km/h

c) t= 45

Step-by-step explanation:

a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km

Duration

= 16 -10

= 6 minutes

b) Average speed

= total distance ÷ total time

Total time

= 24min

= (24÷60) hr

= 0.4 h

Average speed

= 28 ÷0.4

= 70 km/h

c) Average speed= total distance/ total time

Average speed

= 80km/h

= (80÷60) km/min

= 1⅓ km/min

1⅓= 28 ÷(t -24)

since duration for return journey is from t=24 mins to t mins.

$\frac{4}{3}$ (t -24)= 28

$\frac{4}{3}$ t - 32= 28

$\frac{4}{3}$ t= 32 +28

$\frac{4}{3}$ t= 60

t= $6 0\div \frac{4}{3}$

t= 45

*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.

Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)

5 0

4 years ago