Since opposite angles of a cyclic quadrilateral are supplementary,
A= 180-101=79°
B= 180-68=112°
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)
moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g
Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05
N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
Answer: This function is linear because it forms a straight line when graphed.
Would appreciate brainly <3
Answer:
The value of g(−2) is smaller than the value of g(4).
Step-by-step explanation:
To solve this, simply plug in the values in the given equation g(x)=8x-2.
g(-2)=8(-2)-2 -----> -18
g(4)=8(4)-2 ------> 30
here it is obvious that -18 is smaller than 30, therefore the value of g(−2) is smaller than the value of g(4).
Answer:
The dance team raised 170$ during the first fundraiser
Step-by-step explanation:
to find how much the first fundraiser earned let's make an equation and make the first fundraiser the variable x
The equation would be:
x+450=620
so we would take away 450 from both sides
x+450-450=620-450
which would make the equation
x=170
meaning that the first fundraiser raised 170$
