Answer:
x=56 and the exterior angle is 116
Step-by-step explanation:
We will call the unknown angle in the triangle y. Angle y and the angle (2x +4) form a straight line so they make 180 degrees.
y + 2x+4 =180
Solve for y by subtracting 2x+4 from each side.
y + 2x+4 - (2x+4) =180 - (2x+4)
y = 180-2x-4
y = 176-2x
The three angles of a triangle add to 180 degrees
x+ y+ 60 = 180
x+ (176-2x)+60 = 180
Combine like terms
-x +236=180
Subtract 236 from each side
-x+236-236 = 180-236
-x = -56
Multiply each side by -1
-1*-x = -56*-1
x=56
The exterior angle is 2x+4. Substitute x=56 into the equation.
2(56)+4
112+4
116
Fist we find the legnth of the diagonal
a^2+b^2=c^2
3^2+4^2=c^2
9+16=c^2
25=c^2
c=5
now the other diagonal
11^2+5^2=c^2
121+25=c^2
146=c^2
sqrt both sides12.083
closest is B
Answer:
it is in quadratic equation meaning you use Plus or minus
Answer:
therefore y= - (x-2)^2 + 5
Step-by-step explanation:
u do this by using this format here ..,
y=a(x-h)^2+k
sub in the vertex points as h=2 and k = 5 , since the 2 is positive its sign will be -2 in the brackets because when solving for x-2=0 it is x=2
y=a(x-2)^2+5
then with your (0,1) points plug that in as y and x
1=a(0-2)^2+5
1=a(-2)^2+5
1=4a+5
1-5=4a
-4=4a
a=-1
therefore y= - (x-2)^2 + 5
