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3 years ago

5(x+4)>2x-7 please help

Mathematics

1 answer:

Alik [6]3 years ago

3 0

Answer:

x > -9

Step-by-step explanation:

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Line segment WX is the radius of circle X, and line segment ZY is the radius of circle Y. Points W, X, C, Y, and Z are all on li

Andrews [41]

Point D is the midpoint of the outer circle that we aim to find the area of

The circle has a diameter of WZ and radii of WC and CZ

We know that YZ=YD=10 cm

Let DC be $x$ and CY be $10-x$

The radius of the outer circle can be written as $8+8+x$ or $10+10-x$ which we can equate to find the value of $x$

$8+8+x=10+10-x$
$16+x=20-x$
$2x=4$
$x=2$

Therefore, the radius of the circle is $8+8+2=18$

And hence the area of the circle is $\pi (18^{2})$ =324 $\pi$

4 0

3 years ago

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Points X and Z are on a number line, and point Y partitions

abruzzese [7]

Answer:

The coordinate of $Z$ is 13.36.

Step-by-step explanation:

According to the statement, we have the following information:

$\frac{XY}{XZ} = \frac{5}{12}$ (1)

$\frac{YZ}{XZ} = \frac{7}{12}$ (2)

$X = 0.4$ (3)

$Y = 5.8$ (4)

From (2), we have the following expression:

$YZ = \frac{7}{12}\cdot XZ$

$Y-Z =\frac{7}{12}\cdot (X-Z)$

$Y - Z = \frac{7}{12}\cdot X -\frac{7}{12}\cdot Z$

$Y-\frac{7}{12}\cdot X = Z-\frac{7}{12}\cdot Z$

$\frac{5}{12}\cdot Z = Y-\frac{7}{12}\cdot X$

$5\cdot Z = 12\cdot Y-7\cdot X$

$Z = \frac{12}{5}\cdot Y-\frac{7}{5}\cdot X$ (5)

If we know that $Y = 5.8$ and $X = 0.4$ , then the coordinate of $Z$ is:

$Z = \frac{12}{5}\cdot (5.8)-\frac{7}{5}\cdot (0.4)$

$Z = 13.36$

The coordinate of $Z$ is 13.36.

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2 years ago

There are 80 seats in the small screen.

DanielleElmas [232]

One quarter of 80 is 20

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3 years ago

Using the least common denominator rename 3/5 and 1/20

UkoKoshka [18]

LCD is 20
3/5 -> 12/20
1/20 -> 1/20

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2 years ago

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The manager of a warehouse would like to know how many errors are made when a product’s serial number is read by a bar-code read

maw [93]

<span>In order to determine the total number of errors that were made by the bar code scanner, we first have to calculate how many total scans were made. Because there were six items scanned 1,000 times each, there were 6,000 total scans made. Next, we have to add up the total number of errors made by each item (36+14+21+39+11+2). As a result, there were a total of 123 errors made during the 6,000 scans.</span>

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3 years ago

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