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kiruha [24]
3 years ago
15

Algorithm and flowchart to find the perimeter and area of square​

Computers and Technology
1 answer:
kupik [55]3 years ago
4 0

Answer:

I can give you the perimeter "algorithm" but not the flowchart.

Here you go:

p = w * 4

p = perimiter,

w = width/height

4 = the amount of sides needed.

perimeter = width * 4

to include both width and height, we would instead use:

perimeter = 2(width+height)

This also works with rectangles ^

--------------------------------------------------------------------------

To find an area, it is just width * height. This is also compatible with rectangles.

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Write an if-else statement that displays 'Speed is normal' if the speed variable is within the range of 24 to 56. If the speed v
kari74 [83]

Answer:

import java.util.Scanner;

public class Speed{

int speed;

public Speed(int speed){

this.speed = speed;

}

public void checkSpeed(){

if(speed >= 24 || speed <= 56){

System.out.println("Speed is normal");

}

else

System.out.println("Speed is abnormal");

}

public static void main(String...args){

Scanner input = new Scanner(System.in);

int userSpeed = 0;

System.out.println("Enter a speed: ");

userSpeed = input.nextInt();

Speed obj1 = new Speed(userSpeed)

obj1.checkSpeed();

}

Explanation:

4 0
3 years ago
What happens when you click on the colors button in excel?
borishaifa [10]
It writes in that color.
7 0
3 years ago
Place a check next to each of the choices that describe an example of proper ergonomics. (more than 1 answer)
alexandr1967 [171]
I think it’s c and d not 100% sure though
4 0
2 years ago
Read 2 more answers
Need some help writing a simple PYTHON Student registration program:
Y_Kistochka [10]

import random

database = {}

while True:

   try:

       user_choice = int(input("Enter your student id to bring up your information (Press enter if you don't have one) : "))

       if user_choice in database:

           print("Student ID:",database[user_choice][0],"\nFirst name:",database[user_choice][1],"\nLast name:",database[user_choice][2],"\nPhone number:",database[user_choice][3],"\nEmail address:",database[user_choice][4],"\nPassword:",database[user_choice][5],"\nPoints:",database[user_choice][6])

   except ValueError:

       name = input("Enter your first name: ")

       last_name = input("Enter your last name: ")

       phone_number = input("Enter your phone number: ")

       email = input("Enter your email address: ")

       password = input("Enter a password: ")

       points = 100

       student_id = random.randint(1,1000)

       while student_id in database:

           student_id = random.randint(1,1000)

       print("Hello,",name,"your student ID is:",student_id)

       database[student_id] = [student_id,name, last_name, phone_number, email, password, points]

I wrote my code in python 3.8. I hope this helps.

6 0
2 years ago
Define a function called strip_punctuation which takes one parameter, a string which represents a word, and removes characters c
DaniilM [7]

Answer:

punctuation_chars = ["'", '"', ",", ".", "!", ":", ";", '#', '@']

def strip_punctuation(strWord):

   for charPunct in punctuation_chars:

       strWord = strWord.replace(charPunct, "")

   return strWord

Explanation:

The function is defined with a single argument.

A for loop is ran to check each character of the the word.

If a punction mark is present as a character in the word, it is removed.

The same word is returned but without the punctuation marks.

8 0
3 years ago
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