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professor190 [17]

2 years ago

15

NOO THESE PEOPLE TOOK AWAY ALL MY POINTS!!!! I USED TO HAVE LIKE 3000 AND IVE BEEN USING BRAINLY FOR LIKE 10 HOURS AND THEY TOOK

IT ALL AWAY!!!!

2 answers:

Thepotemich [5.8K]2 years ago

6 0

Im so sorry about that

harina [27]2 years ago

3 0

Answer:

I am so sorry they suck and they are stupid

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DUDE SOMEONE ANSWER THIS QUESTION

son4ous [18]

The line which rises to the left has slope of -1/3 and y intercept of 2 so we have

y = -1/3x + 2

3y = -x + 6

x + 3y = 6

Shading is below and the line is solid so the inequality is

x + 3y ≤ 6

The other line has equation

y = 3x - 1

and inequality is

y ≥ 3x - 1

The answer is B

8 0

3 years ago

You have 80 pieces of fabric to make a wall hanging. Each piece of fabric is a square with a side length of 5 inches. You use as

ahrayia [7]

The are would be 25

and we could make 3 squares. 75

5inches will be left over.

8 0

2 years ago

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Decide if the function is an exponential growth function or exponential decay function, and describe its end behavior using limi

____ [38]

Answer:

The answer is (d)

Exponential decay function

$\lim_{x \to -\infty} f_x=0$

$\lim_{x \to \infty} f_x= \infty$

Step-by-step explanation:

∵ y = 0.8^x

∵ 0.8 < 1

∴ 0.8^x is decreasing ⇒ exponential decay function

Ex: 0.8^-4 = 2.441 ⇒ 0.8^4 = 0.4096

when x increase the value of 0.8^x decrease

$\lim_{n \to -\infty} f_x=0.8^{-\infty} = \frac{1}{0.8^{\infty}}=0$

$\lim_{x \to \infty} f_x=0.8^{\infty}=\infty$

∴ The answer is (d)

5 0

3 years ago

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Find z 1 ÷ z 2 for z 1 = 9(cos225° + isin225°) and z 2 = 3(cos45° + isin45°).

olga nikolaevna [1]

$\bf \qquad \textit{division of two complex numbers} \\\\ \cfrac{r_1[cos(\alpha)+isin(\alpha)]}{r_2[cos(\beta)+isin(\beta)]}\implies \cfrac{r_1}{r_2}[cos(\alpha - \beta)+isin(\alpha - \beta)] \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \begin{cases} z1=9[cos(225^o)+i~sin(225^o)]\\\\ z2=3[cos(45^o)+i~sin(45^o)] \end{cases}\implies \cfrac{z1}{z2}\implies \cfrac{9[cos(225^o)+i~sin(225^o)]}{3[cos(45^o)+i~sin(45^o)]} \\\\\\ \cfrac{9}{3}[cos(225^o-45^o)+isin(225^o-45^o)]\implies 3[cos(180^o)+i~sin(180^o)] \\\\\\ 3[(-1)+i~(0)]\implies -3+0i$

8 0

3 years ago

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Jimmy invest $16,000 in an account that pays 7.03% compounded quarterly. How long (in years and months) will it take for his inv

Vladimir [108]

To solve this we are going to use the compound interest formula $A=P(1+ \frac{r}{n})^{nt}$
where:
$P$ is the investment
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year
$t$ is the time in years
$A$ is the amount after $t$ years

First, lets convert the interest rate to decimal dividing it by 100%:
$r= \frac{7.03}{100} =0.0703$
Next, lets find $n$ . Since we know that the interest is compounded every 4 months (quarterly), it will be compounded $\frac{12}{4} =3$ times in a year, so $n=4$ .
We also know that $A=23000$ and $P=16000$ , so lets replace all the quantities into our compound interest formula:
$25000=16000(1+ \frac{0.0703}{3})^{3t}$
$25000=16000(1.0234)^{3t}$

Notice that the the number of years $t$ is in the exponent, so we have to use logarithms to bring it down. But first lets divide both sides by 16000 to isolate the exponential expression:
$\frac{25000}{16000} =(1.0234)^{3t}$
$(1.0234)^{3t} = \frac{25}{16}$
$ln(1.0234)^{3t} =ln( \frac{25}{16} )$
$t= \frac{ln( \frac{25}{16}) }{3ln(1.0234)}$
$t=6.43$

Now that we know $t=6.43$ , the last thing to do is convert 0.43 years to months:
$(0.43 years)( \frac{12months}{1year} )=5.16months$

We can conclude that Jimmy's investment will take 6 years and 5 months to reach $25,000.

6 0

2 years ago