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Yuliya22 [10]
3 years ago
7

Mackenzie invested $770 in an account paying an interest rate of 6.1% compounded

Mathematics
1 answer:
sattari [20]3 years ago
6 0

Answer:

14

Step-by-step explanation:

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Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:
Vikentia [17]

Answer:

a

   \= x  = 18.5  ,  \sigma =  5.15

b

 15.505 < \mu <  21.495

c

 14.93 < \mu <  22.069

Step-by-step explanation:

From the question we are are told that

    The  sample data is  21, 14, 13, 24, 17, 22, 25, 12

     The sample size is  n  = 8

Generally the ample mean is evaluated as

        \= x  =  \frac{\sum x  }{n}

        \= x  =  \frac{  21 + 14 + 13 + 24 + 17 + 22+ 25 + 12  }{8}

         \= x  = 18.5

Generally the standard deviation is mathematically evaluated as

         \sigma =  \sqrt{\frac{\sum (x- \=x )^2}{n}}

\sigma =  \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}

\sigma =  5.15

considering part b

Given that the confidence level is  90% then the significance level is evaluated as

         \alpha  =  100-90

         \alpha  = 10\%

         \alpha  = 0.10

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.645

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.645  *  \frac{5.15 }{\sqrt{8} }

=>     E =  2.995

The 90% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 -  2.995 < \mu <  18.5 +  2.995

       15.505 < \mu <  21.495

considering part c

Given that the confidence level is  95% then the significance level is evaluated as

         \alpha  =  100-95

         \alpha  = 5\%

         \alpha  = 0.05

Next we obtain the critical value of  \frac{ \alpha }{2}  from the normal distribution table the value is  

     Z_{\frac{ \alpha }{2} }  =  1.96

The margin of error is mathematically represented as

      E =  Z_{\frac{ \alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>    E =1.96  *  \frac{5.15 }{\sqrt{8} }

=>     E = 3.569

The 95% confidence interval is evaluated as

       \= x  -  E < \mu <  \= x +  E

substituting values

       18.5 - 3.569 < \mu <  18.5 +  3.569

       14.93 < \mu <  22.069

8 0
3 years ago
What is z- 4/4 +8 simplified?​
vova2212 [387]

Answer:

aw baby naw that not cool

Step-by-step explanation:

3 0
2 years ago
You are making a welding fixture and must cut down a length of copper tubbing from 15 1/8 inches to 8 3/4 inches. If the leftove
Bumek [7]

Answer:   6\dfrac{3}{8}\text{ inches}

Step-by-step explanation:

Given: Original length = 15\dfrac{1}{8} inches

=\dfrac{8\times15+1}{8}=\dfrac{121}{8} inches                      ( In improper fraction )

Length of piece cut from original = 8\dfrac{3}{4} inches

=\dfrac{4\times8+3}{4}= \dfrac{35}{4} inches                 ( In improper fraction )

Length of piece leftover piece =  (Original length ) - (Length of piece cut )

=\dfrac{121}{8}-\dfrac{35}{4}\\\\=\dfrac{121-2\times35}{8}\\\\=\dfrac{121-70}{8}\\\\=\dfrac{51}{8}\\\\=6\dfrac{3}{8}\text{ inches}

Hence, the leftover piece will be 6\dfrac{3}{8}\text{ inches}  long.

6 0
3 years ago
What is the domain of the function graphed below?​
vlabodo [156]

Answer:

x < 7

Step-by-step explanation:

the domain of a function defines the valid x values for the function.

as we go from left to right through all possible values of x, we see all values incl. x=-1 are creating a valid function result (y) for this function. until we reach x=7.

the empty ball indicates that there is no y value defined here. and for any value x>7 there is no y value defined.

so, x < 7 is the right one.

5 0
3 years ago
(URGENT) I just need to know how you do this... please give a detailed answer on what to do!
enyata [817]
You simplify the equation and you use a x y chart and once you get all the points from simplifying the equation you graph those points on the graph chart then connect them
4 0
3 years ago
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