For every 4 minutes he runs, he walks for 5 minutes. Yesterday he walked for 35 minutes. How many minutes did he run?

Nezavi [6.7K]

Answer:

Mid-point: $(0,-5)$

Equation: $y=\frac{7}{3}x-5$

Step-by-step explanation:

To find the mid-point of AB, simply add up their x and y coordinates and divide by 2 respectively to find their middle point.

$(\frac{{x__A}+{x__B}}{2},\frac{{y__A}+{y__B}}{2})$

$(\frac{{-7}+{7}}{2},\frac{{-2}+{(-8)}}{2})$

$(0,-5)$

To find the perpendicular slope that passes through the mid-point, we need to know the slope between AB first.

Slope of AB: $\frac{{y__2}-{y__1}}{{x__2}-{x__1}}$ = $\frac{{-8}-{-2)}}{{7}-{(-7)}}$ = $\frac{-6}{14}$ = $\frac{-3}{7}$

Multiplying slopes that are perpendicular with each other always results in -1.

$\frac{-3}{7}*m = -1$

$m=\frac{7}{3}$

By the point slope form:

$({y}-{y__1})=m({x}-{x__1})$

Plug in the coordinates of the mid-point:

$({y}-{(-5)})=\frac{7}{3} ({x}-{0})$

Equation: $y=\frac{7}{3}x-5$

6 0

2 years ago

Determine the relative order of the metric prefixes of kilo-, micro-, centi-, and milli-.

nadya68 [22]

The relative order of the metric prefixes is micro-, milli-, centi- and kilo-,

<h3>What are metric units?</h3>

Metric units are units used to measure quantities

The units are given as:

kilo-, micro-, centi-, and milli-

In metric units, the value of each prefix is:

Kilo = 1000

Micro = 0.0001

Centi = 100

Milli = 0.1

In order of arrangement, we have:

Micro = 0.0001

Milli = 0.1

Centi = 100

Kilo = 1000

Hence, the relative order of the metric prefixes is micro-, milli-, centi- and kilo-,

Read more about metric units at:

brainly.com/question/2555957

8 0

2 years ago

Please help! Ill mark brainliest if correct! help ASAP

amm1812

Answer:

Its 1,020

Hope u get it right!!!

U got this!!!!!!!!!!

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

I NEED HELP PLEASE HELP

Elanso [62]

Answer:

66.) 1.) M=-9/7

2.) Y-INTERCEPT (9)

3.) X-INTERCEPT (7).

7 0

2 years ago

Read 2 more answers

Assume that adults were randomly selected for a poll. They were asked if they "favor or oppose using federal tax dollars to fund

ser-zykov [4K]

Testing the hypothesis, it is found that since the p-value of the test is 0.0042 < 0.01, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

At the null hypothesis, it is tested if the proportion is of 0.5, that is:

$H_0: p = 0.5$

At the alternative hypothesis, it is tested if the proportion is different of 0.5, that is:

$H_1: p \neq 0.5$

The test statistic is given by:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}$

In which:

$\overline{p}$ is the sample proportion.
p is the value tested at the null hypothesis.
n is the sample size.

In this problem, the parameters are given by:

$p = 0.5, n = 483 + 398 = 881, \overline{p} = \frac{483}{881} = 0.5482$

The value of the test statistic is:

$z = \frac{\overline{p} - p}{\sqrt{\frac{p(1 - p)}{n}}}$

$z = \frac{0.5482 - 0.5}{\sqrt{\frac{0.5(0.5)}{881}}}$

$z = 2.86$

Since we have a two-tailed test(test if the proportion is different of a value), the p-value of the test is P(|z| > 2.86), which is 2 multiplied by the p-value of z = -2.86.

Looking at the z-table, z = -2.86 has a p-value of 0.0021.

2(0.0021) = 0.0042

Since the p-value of the test is 0.0042 < 0.01, it can be concluded that the proportion of subjects who respond in favor is different of 0.5.

A similar problem is given at brainly.com/question/24330815

3 0

2 years ago