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Paraphin [41]
3 years ago
5

Sorry for the bad quality.

Mathematics
1 answer:
ser-zykov [4K]3 years ago
8 0

Answer:

B and C

Step-by-step explanation:

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Simplify this algebra expression:<br><br> 6j-2j-2j+8+9+6e+5
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Answer:

6j-2j-2j+8+9+6e+5

= 6j - 4j + 6e + 24

= 2j + 6e + 24

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value of the expression \frac{1.6(10^{5})}{0.2(10^{2})} or   1.6(10^{5}) over 0.2(10^{2})  is 8000 (8 \times 10 ^3).

<u>Step-by-step explanation:</u>

Here we have , to find the value of the expression shown below  1.6 x 10 to the 5th power over 0.2 x 10 to the 2nd power i.e. 1.6(10^{5}) over 0.2(10^{2}) :

⇒  1.6(10^{5}) over 0.2(10^{2})

⇒ \frac{1.6(10^{5})}{0.2(10^{2})}

multiply and divide by 10 to remove decimals, so we get

⇒ \frac{16(10^{5})}{2(10^{2})}

⇒ \frac{8(2)(10^{5})}{2(10^{2})}

⇒ 8\frac{(10^{5})}{(10^{2})}

⇒ 8(10^{(5-2)})

⇒ 8(10^{3})

⇒ 8(1000)

⇒ 8000

Therefore, value of the expression \frac{1.6(10^{5})}{0.2(10^{2})} or   1.6(10^{5}) over 0.2(10^{2})  is 8000 (8 \times 10 ^3).

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