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skad [1K]
2 years ago
13

Find the smallest number which is exactly divisibleby 15 20 and 30​

Mathematics
1 answer:
Svetach [21]2 years ago
7 0

Answer:

60

Step-by-step explanation:

The smallest number that is divisible by 15, 20 , and 30, must have the needed factors of each of these numbers:

15 = 3 * 5

20 = 2 * 2 * 5

30 = 2 * 3 * 5

Then the minimum common factor must have the following factors to satisfy the divisibility of all of the numbers above:

2 * 2 * 3 * 5 = 60

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Answer:

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