The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.
We need the answer in cubic centimeters. So let's convert 350 cubic inches to cubic centimeters. We will do it unit conversion way (the long way).
We will write cubic inches as three inches side-by-side
350 in^3
<h3>What is the ratio of the centimeter?</h3>
This way, we can multiply this by the ratio of centimeters to inches [2.54 cm = 1 inch], so that the units cancel and we have cubic centimeters (what we desire).
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in
So, we can cancel the three inches top and bottom thus we have the answer in centimeters cubed. And the value is
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in.
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in=5735.47.
So 350 cubic inches is approximately 5735.5 cubic centimeters (rounded to 1 decimal place).
This is larger than a 5500 cubic centimeters engine.
5735.5-5500=235.5cubic centimeters.
The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.
To learn more about the significant figures visit:
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X=number total of student at the school.
70% of x=161
can suggest this equation:
(70/100)x=161
0.7x=161
x=161/0.7=230
Answer: the school has 230 students
Answer:
See below ~
Step-by-step explanation:
<u>P (6th grader)</u>
- No. of 6th graders / Total students
- 6 / 6 + 7 + 8
- 6/21
- 2/7
<u>P (6th grader after)</u>
- No. of 6th graders - 1 / Total students - 1
- 6 - 1 / 21 - 1
- 5/20
- 1/4
<u>Question 1 : P (Both 6th graders)</u>
- P = P (6th grader) × P (6th grader after)
- P = 2/7 x 1/4 = 2/28 = <u>1/14</u>
<u></u>
<u>Question 2 : P' (Both 6th graders)</u>
- P' = 1 - P
- P' = 1 - 1/14
- P' = <u>13/14</u>
<h3>Answer: x = 5</h3>
=====================
Work Shown:
Angle Bisector Theorem
9/(2x-1) = 15/3x
9*3x = 15(2x-1) ... cross multiply
27x = 30x-15
27-30x = 30x-15-30x ... subtract 30x from both sides
-3x = -15
-3x/(-3) = -15/(-3) .... divide both sides by -3
x = 5
Yes, it this somehow related to mathematics? Was this a question?