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scZoUnD [109]
3 years ago
5

Please help #platogang

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
8 0

Answer:

it is 54

Step-by-step explanation:

1=1

2=4

5=7

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He total variance is $35000 f. the total materials variance is $14000 f. the total labor variance is twice the total overhead va
TiliK225 [7]
Assume that the total overhead variance is x
We are given that the total labor variance is twice the total overhead variance. This means that, the total labor variance is 2x

Total variance can be calculated as follows:
Total variance = Total materials variance + Total overhead variance
                          + Total labor variance

We have:
Total variance = $35000
Total materials variance = $14000
Total overhead variance = x
Total labor variance = 2x

Substitute in the equation and solve for x as follows:
35000 = 14000 + x + 2x
35000 - 14000 = 3x
21000 = 3x
x = 21000/3
x = 7000

Based on the above calculations:
Total overhead variance = x = $7000
Total labor variance = 2x = 2*7000 = $14000
4 0
3 years ago
What ratio is equivalent to the ratio 9:10
Tatiana [17]
18:20

Multiply each side by 2
6 0
3 years ago
Read 2 more answers
Consider a function that describes how a particular cars gas mileage depends on its speed. What would be an appropriate domain f
Elina [12.6K]

gas mileage = k*s, where k is a constant of proportionality and s is the speed. Unfortunately, this does not take into account the fact that the engine consumes fuel even when the car is not moving.


Here it makes most sense to regard {0, S} as the domain for this function. Here, S would represent the car's top speed.


8 0
4 years ago
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Find the mean of:<br> 16 32 10 28 8 19 32 26<br> 33 39 98 399
iren2701 [21]

Answer:

91.125

Step-by-step explanation:

Total number/ Total number of quantity

16+32+10+28+8+19+32+26+33+39+98+399

729

Divode by number of quantity (8)

729/8

=91.125

Hope this helps, dont hesitate to Ask in comment below. Mark me as brainliest also appriciated!!

5 0
3 years ago
Assume the readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees
lozanna [386]

Answer: 0.0035

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.

i.e.  \mu=0 and \sigma= 1  

Let x denotes the readings on thermometers.

Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_

P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035

Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035

The required region is attached below .

8 0
3 years ago
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