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Helga [31]
3 years ago
10

Really desperate!

Computers and Technology
2 answers:
bija089 [108]3 years ago
7 0

Answer: Sorry to break this to you but you can't.

Explanation:

SIZIF [17.4K]3 years ago
6 0

Answer: Before we get started, make a backup of any local files you have on the Chromebook. Your Chromebook will be <u>Powerwashed</u> in the process, erasing any accounts and local data. With that all done, let's enable developer mode!

  • Boot your Chromebook into <u>recovery mode</u> by holding the <u>Esc and Refresh (the circular arrow) keys</u> while pressing the <u>power button.</u> If you are using a Chromebook or Chromebit, there will be a hole on the device that has the recovery button inside. Stick a paperclip or similar object inside to hold down the recovery button, then press the power button.

  • <u>Press Ctrl + D</u> on your keyboard when asked to insert recovery media.

  • Press <u>Enter</u> to confirm.

  • When your device reboots, you'll see a screen stating the OS verification is off. This screen will appear every time you turn the device on to warn you that the device isn't as secure as it would be out of the box. When you see this screen, <u>press Ctrl + D</u> to continue booting, or wait a few seconds and the device will boot on its own.

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konstantin123 [22]

Answer:

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Explanation:

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3 years ago
NAND is logically complete. Use only NAND gates to constructgate-level circuits that compute the
Drupady [299]

Answer:

Hi, for this exercise we have two laws to bear in mind:

Morgan's laws

NOT(А).NOT(В) = NOT(A) + NOT (B)

NOT(A) + NOT (B) = NOT(А).NOT(В)

And the table of the Nand

INPUT OUTPUT

A B A NAND B

0 0         1

0 1         1

1 0         1

1 1         0

Let's start!

a.

Input            OUTPUT

A       A     A NAND A

1         1             0

0        0            1

b.

Input            OUTPUT

A       B     (A NAND B ) NAND (A NAND B )

0         0            0

0         1            0

1          0             0

1          1             1

C.

Input            OUTPUT

A       B     (A NAND A ) NAND (B NAND B )

0        0           0

0        1             1

1         0            1

1          1            1

Explanation:

In the first one, we only need one input in this case A and comparing with the truth table we have the not gate

In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.

In the third case we have that the OR is A + B and we know in base of the morgan's law that:

A + B = NOT(NOT(А).NOT(В))

So, we have to negate the two inputs and after make nand with the two inputs negated.

I hope it's help you.

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I believe A is the answer here.

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