Answer:
No, Ivory is incorrect. The equation does have a solution, and the solution is x = -1.
Step-by-step explanation:
We try to solve the equation first.
2x + 2 = x + 1
We want all variables on the left side and all numbers on the right side.
Subtract x from both sides.
x + 2 = 1
Subtract 2 from both sides.
x = -1
Check: Plug in -1 for x on both sides and see if it makes a true statement.
2x + 2 = x + 1
2(-1) + 2 = -1 + 1
-2 + 2 = 0
0 = 0
0 = 0 is a true statement, so the solution x = -1 is the correct solution.
Answer: Ivory is incorrect. The equation does have a solution, and the solution is x = -1.
A integer for -4 would be +4
A equation to represent this situation is:

Now we have to find x.
Step 1: Subtract 0.5x from both sides.
<span><span><span><span>0.75x</span>+7.5</span>−<span>0.5x</span></span>=<span><span><span>0.5x</span>+10</span>−<span>0.5x</span></span></span><span><span><span>0.25x</span>+7.5</span>=10
</span>Step 2: Subtract 7.5 from both sides.
0.25x+7.5−7.5=10−7.50.25x=2.5
Step 3: Divide both sides by 0.25.
<span><span><span>0.25x/</span>0.25</span>=<span>2.5/<span>0.25
</span></span></span>Answer:
<span>x=<span>10</span></span>
They will cost the same after 10 rides.
Answer:
odd
Step-by-step explanation:
Just so you know there are shortcuts for determining if a polynomial function is even or odd. You just to make sure you use that x=x^1 and if you have a constant, write it as constant*x^0 (since x^0=1)
THEN!
If all of your exponents are odd then the function is odd
If all of your exponents are even then the function is even
Now you have -4x^3+4x^1
3 and 1 are odd it is an odd function
This a short cut not the legit algebra way
let me show you that now:
For it to be even you have f(-x)=f(x)
For it be odd you have f(-x)=-f(x)
If you don't have either of those cases you say it is neither
So let's check
plug in -x -4(-x)^3+4(-x)=-4*-x^3+-4x=-4x^3+-4x
that's not the same so not even
with if we factor out -1 .... well if we do that we get -(4x^3+4x)=-f(x)
so it is odd.
Answer:
B
Step-by-step explanation: