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Andrew [12]
4 years ago
14

use the digits 1, 2, 3, 4 and 5 so the quotient is greater than 200 and the reminder is zero. Use each digit only once. 9635 / x

x = xxx
Mathematics
1 answer:
Ludmilka [50]4 years ago
7 0
\frac{9635}{xx}=xxx\\\\9635=5\cdot41\cdot47=41\cdot235\\\\Answer:\frac{9635}{41}=235
You might be interested in
Kenji packed an exercise ball into a cylindrical package . How much space does the package occupy in terms of pi . Enter your an
grandymaker [24]

Answer:

The space that the package would occupy is 45\pi cubic feet.

Step-by-step explanation:

The space that the package occupies is the volume of the cylinder. The volume of an object is the 3 dimensional capacity of the object.

Volume of a cylinder = \pir^{2}h

where: r is the radius and h is the height of the cylinder.

Given that; h = 5 feet and r = 3 feet.

The required volume = \pi × (3)^{2} × 5

                                   = \pi  × 9 × 5

                                  = 45\pi cubic feet

The space that the package would occupy is 45\pi cubic feet.

3 0
3 years ago
Algebra need some assistance
d1i1m1o1n [39]
X=0,2,3/8
That is what x equal i don’t know the question but I hope this help
5 0
3 years ago
NEED URGENT HELP!! WILL GIVE BRAINLIEST
Flauer [41]

1. You need to multiply the denominator by something that will make the content of the radical be a square—so that when you take the square root, you get something rational. Easiest and best is to multiply by √6. Of course, you must multiply the numerator by the same thing. Then simplify.

\displaystyle\frac{2}{\sqrt{6}}=\frac{2}{\sqrt{6}}\cdot\frac{\sqrt{6}}{\sqrt{6}}\\\\=\frac{2\sqrt{6}}{\sqrt{6}\cdot\sqrt{6}}=\frac{2\sqrt{6}}{6}\\\\=\bf{\frac{\sqrt{6}}{3}}

2. Identify the squares under the radical and remove them.

5\sqrt{12xm^3}=5\sqrt{(4m^2)(3xm)}=5\sqrt{(2m)^2}\sqrt{3xm}\\\\=5\cdot 2m\sqrt{3xm}=\bf{10m\sqrt{3xm}}

7 0
3 years ago
Read 2 more answers
3.) SOLVE FOR X.
gayaneshka [121]

The value of x in the secants intersection is 1 units

The value of NM in the tangent and secant intersection is 51 units

<h3>How to find length when secant and tangent intersect?</h3>

The first question, two secant intersect outside the circle.

Therefore,

(6x + 8x)8x = (9 + 7)7

14x(8x) = 16(7)

112x² = 112

x² = 112 / 112

x = √1

x = 1

The second question, tangent and secant intersect,

Therefore,

(x + 3)² = (x - 3)(16 + x - 3)

(x + 3)² = (x - 3)(x + 13)

(x + 3)(x + 3) = (x - 3)(x + 13)

x² + 3x + 3x + 9 = x² + 13x - 3x - 39

x² + 9x + 9 = x² + 10x - 39

x² - x² + 9x - 10x = -39 - 9

-x = - 48

x = 48

NM = 48 + 3 = 51 units

learn more on secant and tangent here: brainly.com/question/12477905

#SPJ1

6 0
2 years ago
Hello<br>mere pyaare bhaiyo or bheno​
goldfiish [28.3K]

Cz I secretly enter this site

Non of my family knows

Cz they are over protective lol

Only a cousin know

That's why l can't pay to comment

It's sad life bro

5 0
3 years ago
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