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3 years ago

In 6n + 8, n is best described as

Mathematics

1 answer:

Harman [31]3 years ago

7 0

<span> n is best described as a unknown variable </span>

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The data represent the results for a test for a certain disease. Assume one individual from the group is randomly selected. Find

SOVA2 [1]

Answer:

0.505 = 50.7% probability of a negative test.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

142 + 6 = 148 people tested positive. Of those, 142 had the disease and 6 did not.

7 + 145 = 152 people tested negative. Of those, 7 had the disease and 145 did not.

Find the probability of getting someone who tests negative, given that he or she did not have the disease.

This is the probability of a negative test.

152 negative tests out of 148 + 152 = 300

152/300 = 0.507

0.505 = 50.7% probability of a negative test.

5 0

3 years ago

HELP ME PLEASE! 20 POINTS!!!

Grace [21]

Answer:

is in the shape of a sphere

diameter = 60 feet

radius = r = 60/2 = 30 feet

Step-by-step explanation:

volume of sphere = 4/3 × π × r³

= 4/3 × π × 30³

=4/3π × 27,000

= 36000π cubic feet

7 0

2 years ago

Read 2 more answers

Seven less than the quotient of x and 9

bulgar [2K]

X/9 - 7 is the answer. note x/9 is in fraction form

8 0

3 years ago

Find the slope of the given line, if it is defined.

il63 [147K]

Answer: A. The slope is $-\dfrac{4}{3}$ .

Step-by-step explanation:

The slope of a line helps to specify the direction of the line.

The slope of a line that passes through (a,b) and (c,d) is given by :-

$\text{Slope}=\dfrac{d-b}{c-a}$

Then the slope of a line passes through origin i.e. (0,0) and (-9,12) is given by :-

$\text{Slope}=\dfrac{12-0}{-9-0}\\\\\Rightarrow\ \text{Slope}=\dfrac{12}{-9}\\\\\Rightarrow\ \text{Slope}=-\dfrac{4}{3}$

Hence, the slope is $-\dfrac{4}{3}$ .

8 0

2 years ago

Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the

sp2606 [1]

Given:

The given quadratic polynomial is :

$x^2-x-12$

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

$x^2-x-12$

Equate the polynomial with 0 to find the zeroes.

$x^2-x-12=0$

Splitting the middle term, we get

$x^2-4x+3x-12=0$

$x(x-4)+3(x-4)=0$

$(x+3)(x-4)=0$

$x=-3,4$

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

$x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}$

$x^2-(3+(-4))x+(3)(-4)$

$x^2-(-1)x+(-12)$

$x^2+x-12$

Therefore, the required polynomial is $x^2+x-12$ .

4 0

3 years ago