Given that the roots of the equation a
align="absmiddle" class="latex-formula">+b
+c=0 are 
and n, show that (n+1)²ac=nb²
1 answer:
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Answer:
x = y + v/b
Step-by-step explanation:
You can solve for x by adding v/b to both sides since that is what will isolate x the quickest and that is what you want to do when you need to solve for something.
By adding v/b to both sides, you will end up with x=y+v/b and that’s your answer!
Hope this helps!
(Credit to math-way)
