Step-by-step explanation:
Let
= mass of the painter
= mass of the scaffold
= mass of the equipment
= tension in the cables
In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as
Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of . The net torque on the scaffold is then
Solving for T,
or
![T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7B9%7D%5Bm_sg%281.9%5C%3A%5Ctext%7Bm%7D%29%20%2B%20m_pg%284.2%5C%3A%5Ctext%7Bm%7D%29%5D)
To solve for the the mass of the equipment , use the value for T into Eqn(1):
I did the math and I believe the answer is, the y-intercept is 12.3.
B. Love miss you have you too she got your
From the problem, the vertex = (0, 0) and the focus = (0, 3)
From the attached graphic, the equation can be expressed as:
(x -h)^2 = 4p (y -k)
where (h, k) are the (x, y) values of the vertex (0, 0)
The "p" value is the difference between the "y" value of the focus and the "y" value of the vertex.
p = 3 -0
p = 3
So, we form the equation
(x -0)^2 = 4 * 3 (y -0)
x^2 = 12y
To put this in proper quadratic equation form, we divide both sides by 12
y = x^2 / 12
Source:
http://www.1728.org/quadr4.htm
