PLZ HELP 3 MINUTES LEFT WIL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Which equation could be used to create the function table A y=3x B y=x+3 C y=4x D y=x+2

Setler79 [48]

A y=3x because 3*1 is 3 and 3*2 is 6 and so on

4 0

3 years ago

Can the integer 27 be simplified

Alex_Xolod [135]

Answer:

yes

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

MULTIPLE CHOICE PLS ANSWER

zubka84 [21]

Answer:

Option.B

Step-by-step explanation:

Its because if you add these two angles you get a supplementary angle or 180°

Using this we can form an equation to find the value of x.

(Hope this answer helps :))

(And is this question from Khan Academy?)

5 0

3 years ago

Plz hurry, brainliest and lots of points plz explain answer and only answer if you are actually gonna do it.

Citrus2011 [14]

Answer and Step-by-step explanation:

1st box:

0, -3

2nd box

-2, -9/4

3rd box:

2, -3/2

4th box:

4, 0

Btw 0, -2, 2, 4 are in the x-coordinate column if you didn’t know, and 1, -9/4, -3/2 are in the y-coordinate column

Basically to solve if you plug in 0 into x, so basically it’s 3(0)-4y=12, which you simplify gives you 0-4y=12, subtract 0 from 12 which is 12 and then do 12 divided by -4 and then you get y = -3 and that’s how you get the box answer

Idk how to the rest srry lol!

3 0

3 years ago

Suppose a lawn and garden company wants to determine the current percentage of customers who use fertilizer on their lawns. How

marishachu [46]

Answer:

n=601

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.04$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have a prior estimation for the proportion we can use 0.5 as estimation. And replacing into equation (b) the values from part a we got:

$n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.96})^2}=600.25$

And rounded up we have that n=601

3 0

3 years ago