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3 years ago

Find the slope of the line that passes through (-20, -51) and (31, -75).

Mathematics

1 answer:

lilavasa [31]3 years ago

7 0

Answer:

-8/17

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-75-(-51))/(31-(-20))

m=(-75+51)/(31+20)

m=-24/51

m=-8/17

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Assume z = x + iy, then find a complex number z satisfying the given equation. d. 2z8 – 2z4 + 1 = 0

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Answer: complex equations has n number of solutions, been n the equation degree. In this case:

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Step-by-step explanation:

I start with a variable substitution:

$Z^{4} = X$

Then:

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Solving the quadratic equation:

$X_{1} =\frac{2+\sqrt{4-4*2*1} }{2*2} \\X_{2} =\frac{2-\sqrt{4-4*2*1} }{2*2}$

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Using this:

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Solving for the modulus and the angle:

$Z=\left \{ {{\sqrt[4]{\frac{\sqrt{2}}{2} e^{i45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i45}} } \atop {\sqrt[4]{\frac{\sqrt{2}}{2} e^{i-45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i-45}} }} \right.$

The possible angle respond to:

$RAng_{12...n} =\frac{Ang +360*(i-1)}{n}$

Been "RAng" the resultant angle, "Ang" the original angle, "n" the degree of the root and "i" a value between 1 and "n"

In this case n=4 with 2 different angles: Ang = 45º and Ang = 315º

Obtaining 8 different angles, therefore 8 different solutions.

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