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Alex Ar [27]
3 years ago
8

Find the Greatest Common Factor of the following numbers. 9, 15 and 36

Mathematics
1 answer:
Triss [41]3 years ago
6 0

Answer:

3

Step-by-step explanation:

Greatest Common Factor is the highest number that divides exactly into two or more numbers. It is the "greatest" thing for simplifying fractions.

3 is divisible by 9, 15, and 36.

You might be interested in
If x is the least common multiple of the set {6, 8, 12} and y is the greatest common factor
Anarel [89]

Answer:

12

Step-by-step explanation:

The least common multiple of {6,8,12} is 24. This can be intuitively figured by noting that any multiple of 12 is a multiple of 6 and that 12 is 1.5x larger than 8. That means we only have so multiple 12 by 2 and 8 by 3 for them to be equal. The GCF of {20,42,72} is 2 as the prime factorization of 20 is 2x2x5 and 42 is 2x3x7. That means even without having to check 72 (which is clearly even so 2 is a factor), we know that 2 is the greatest common factor that they could share. So X/Y = 24/2 = 12

8 0
3 years ago
The quadratic function f (x) = - 45x2 + 350x + 1,590 models the population of a city where x represents the number of years sinc
kramer

Answer: 2,215,000

Step-by-step explanation:

Given: The quadratic function f (x) = - 45x^2 + 350x + 1,590 models the population of a city where x represents the number of years since 2005.

To Find:  population of the city in 2010

We need to put x= 2010-2005 = 5

f (5) = - 45(5)^2 + 350(5) + 1,590\\\\=-1125+1750+1590 =2215

Hence, the estimated population of the city in 201 = 2215 thousands or 2,215,000 .

3 0
3 years ago
The lengths of bolts in a batch are distributed normally with a mean of 3 cm and a standard
ValentinkaMS [17]

Answer:

0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 3 cm and a standard deviation of 0.04 cm.

This means that \mu = 3, \sigma = 0.04

What is the probability that a bolt has a length greater than 2.96 cm?

This is 1 subtracted by the p-value of Z when X = 2.96. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.96 - 3}{0.04}

Z = -1

Z = -1 has a p-value of 0.1587.

1 - 0.1587 = 0.8413

0.8413 = 84.13% probability that a bolt has a length greater than 2.96 cm.

3 0
3 years ago
Select the correct answer from each drop-down menu. Right triangle ABC is represented with the right angle at vertex B. Base BC
Svetradugi [14.3K]

By using trigonometric relations, we will see that:

AC = 15.6 in

AB = 8.4 in.

<h3>How to get the measures of the other two sides of the right triangle?</h3>

Here we have the right triangle where:

B = 90°

C = 40°

BC = 10 in.

Notice that is the adjacent cathetus to the angle C, then we can use the two relations:

  • sin(a) = (adjacent cathetus)/(hypotenuse).
  • tan(a) = (opposite cathetus)/(adjacent cathetus).

Where:

  • hypotenuse = AC
  • opposite cathetus = AB.

Then we will have:

sin(40°) = 10in/AC.

AC = 10in/sin(40°) = 15.6 in

tan(40°) = AB/10in

tan(40°)*10in = AB = 8.4 in.

So we can conclude that for the given right triangle we have:

AC = 15.6 in

AB = 8.4 in.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

6 0
2 years ago
..................................
yanalaym [24]

Answer:

The answer is a² .

Step-by-step explanation:

You have to substitute x and y into the expression :

let \: x = a \cos(θ) \\ let \: y = a \sin( θ)

{x}^{2}  +  {y}^{2}  =  {(a \cosθ )}^{2}  +  {(a \sinθ) }^{2}

{x}^{2}  +  {y}^{2}  =  {a}^{2}( {cos}^{2}θ) +  {a}^{2} ({sin}^{2}θ)

Next, you have to apply Basic Trigonometric Identity :

{sin}^{2} θ +  {cos}^{2} θ = 1

{x}^{2}  +  {y}^{2}  =  {a}^{2} ( {cos}^{2} θ +  {sin}^{2} θ)

{x}^{2}  +  {y}^{2}  =  {a}^{2} (1)

{x}^{2}  +  {y}^{2}  =  { a}^{2}

8 0
3 years ago
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