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Fynjy0 [20]
3 years ago
14

The scale on a map shows that 10 kilometers is represented by 4 centimeters. Which proportion can be used to find the actual dis

tance, x, represented by 20 centimeters on the map? StartFraction 10 over 4 EndFraction = StartFraction x over 20 EndFraction StartFraction 10 over 4 EndFraction = StartFraction 20 over x EndFraction StartFraction 10 over 20 EndFraction = StartFraction 4 over x EndFraction StartFraction 10 over 20 EndFraction = StartFraction x over 4 EndFraction
HELP PLSS QUICK ILL GIVE BRAINLIST
Mathematics
2 answers:
Usimov [2.4K]3 years ago
5 0
10/4=x/20
Your answer will be x=50 kilometers
ololo11 [35]3 years ago
3 0

Answer:

the guy above me is correct

Step-by-step explanation:

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Which is true about the solution to the system of inequalities shown? y less than or equal to 1/3x-1 and y less than or equal to
tekilochka [14]
Y≤x/3-1  AND y≤x/3-3

So for BOTH inequalities to be true:

y≤x/3-3


4 0
3 years ago
If u, v, and w are nonzero vectors in r 2 , is w a linear combination of u and v?
Tju [1.3M]
Not necessarily. \mathbf u and \mathbf v may be linearly dependent, so that their span forms a subspace of \mathbb R^2 that does not contain every vector in \mathbb R^2.

For example, we could have \mathbf u=(0,1) and \mathbf v=(0,-1). Any vector \mathbf w of the form (r,0), where r\neq0, is impossible to obtain as a linear combination of these \mathbf u and \mathbf v, since

c_1\mathbf u+c_2\mathbf v=(0,c_1)+(0,-c_2)=(0,c_1-c_2)\neq(r,0)

unless r=0 and c_1=c_2.
8 0
3 years ago
An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan
AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=x_{0}]

In this case 95% prediction interval for Y/X=0.5

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

I hope it helps!

6 0
3 years ago
A property owner wants to build a cyclone fence around their property. The lot is rectangular, 110 feet by 270 feet. The fence i
dimulka [17.4K]

Answer:

total cost= $5,814

Step-by-step explanation:

Total linear feet measured: (110 x 2) + (270 x 2) = 760 linear ft

total sq ft= 760 x (7) = 5320 sq ft

total linear ft x labor= 760 x 1.70 = 1292 labor

Total sq ft x Cyclone fencing cost= 5320 x .85 = 4522

the total cost is 1292 + 4522 = $5,814

8 0
4 years ago
HELPPP MY MATH HOMEWORK!!!
11Alexandr11 [23.1K]
D and then A I would say
7 0
3 years ago
Read 2 more answers
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